Discover how IDNLearn.com can help you learn and grow with its extensive Q&A platform. Ask your questions and receive reliable and comprehensive answers from our dedicated community of professionals.
Sagot :
Sure, let's solve these problems step by step and express the answers to the correct number of significant figures.
1. Divide [tex]\( \frac{2.31}{0.790} \)[/tex]:
First, perform the division:
[tex]\[ \frac{2.31}{0.790} = 2.9240506329113924 \][/tex]
The result needs to be expressed in scientific notation with 5 significant figures. This would be:
[tex]\[ 2.92405 \times 10^0 \][/tex]
2. Multiply [tex]\( (2.08 \times 10^3) \times (3.11 \times 10^2) \)[/tex]:
First, multiply the coefficients:
[tex]\[ 2.08 \times 3.11 = 6.4648 \][/tex]
Then, add the exponents for powers of 10:
[tex]\[ 10^3 \times 10^2 = 10^{3+2} = 10^5 \][/tex]
Putting it all together:
[tex]\[ 6.4648 \times 10^5 = 646480.0 \][/tex]
Given the answer should be to the correct number of significant figures (3 significant figures from 2.08 and 3.11):
[tex]\[ 6.47 \times 10^5 = 647000 \][/tex]
### Summary:
- For [tex]\( \frac{2.31}{0.790} \)[/tex]:
[tex]\[ 2.92405 \times 10^0 \][/tex]
- For [tex]\( (2.08 \times 10^3) \times (3.11 \times 10^2) \)[/tex]:
[tex]\[ 647000 \][/tex]
So, filling in the boxes:
[tex]\[ \begin{array}{l} \frac{2.31}{0.790}=2.92405 \times 10^0 \\ \left(2.08 \times 10^3\right) \times\left(3.11 \times 10^2\right)=647000 \end{array} \][/tex]
1. Divide [tex]\( \frac{2.31}{0.790} \)[/tex]:
First, perform the division:
[tex]\[ \frac{2.31}{0.790} = 2.9240506329113924 \][/tex]
The result needs to be expressed in scientific notation with 5 significant figures. This would be:
[tex]\[ 2.92405 \times 10^0 \][/tex]
2. Multiply [tex]\( (2.08 \times 10^3) \times (3.11 \times 10^2) \)[/tex]:
First, multiply the coefficients:
[tex]\[ 2.08 \times 3.11 = 6.4648 \][/tex]
Then, add the exponents for powers of 10:
[tex]\[ 10^3 \times 10^2 = 10^{3+2} = 10^5 \][/tex]
Putting it all together:
[tex]\[ 6.4648 \times 10^5 = 646480.0 \][/tex]
Given the answer should be to the correct number of significant figures (3 significant figures from 2.08 and 3.11):
[tex]\[ 6.47 \times 10^5 = 647000 \][/tex]
### Summary:
- For [tex]\( \frac{2.31}{0.790} \)[/tex]:
[tex]\[ 2.92405 \times 10^0 \][/tex]
- For [tex]\( (2.08 \times 10^3) \times (3.11 \times 10^2) \)[/tex]:
[tex]\[ 647000 \][/tex]
So, filling in the boxes:
[tex]\[ \begin{array}{l} \frac{2.31}{0.790}=2.92405 \times 10^0 \\ \left(2.08 \times 10^3\right) \times\left(3.11 \times 10^2\right)=647000 \end{array} \][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Your questions deserve precise answers. Thank you for visiting IDNLearn.com, and see you again soon for more helpful information.