IDNLearn.com: Your destination for reliable and timely answers to any question. Join our platform to receive prompt and accurate responses from experienced professionals in various fields.

For the simple harmonic motion equation [tex]$d=9 \cos \left(\frac{\pi}{2} t\right)$[/tex], what is the maximum displacement from the equilibrium position?

Answer here:
[tex]$\qquad$[/tex]


Sagot :

To find the maximum displacement from the equilibrium position for the given simple harmonic motion equation [tex]\( d = 9 \cos \left( \frac{\pi}{2} t \right) \)[/tex], follow these steps:

1. Identify the Amplitude: The equation of simple harmonic motion provided is in the form [tex]\( d = A \cos(\omega t) \)[/tex], where [tex]\( A \)[/tex] is the amplitude and [tex]\( \omega \)[/tex] is the angular frequency. In our case, the equation is [tex]\( d = 9 \cos \left( \frac{\pi}{2} t \right) \)[/tex].

2. Maximum Value of Cosine Function: The cosine function [tex]\( \cos(x) \)[/tex] can take values between -1 and 1. Therefore, its maximum value is 1.

3. Calculate Maximum Displacement: The maximum displacement from the equilibrium position occurs when the cosine function attains its maximum value, which is 1.
[tex]\[ d_{\text{max}} = 9 \cdot 1 = 9 \][/tex]

Thus, the maximum displacement from the equilibrium position is:
[tex]\[ \boxed{9} \][/tex]