Explore IDNLearn.com's extensive Q&A database and find the answers you're looking for. Get the information you need from our community of experts, who provide detailed and trustworthy answers.
Sagot :
To calculate the molarity of a solution, follow these steps:
1. Identify the given values:
- Mass of solute (solute here is [tex]\(K_2O_3\)[/tex]): 10 grams
- Volume of the solution: 300 milliliters
- Molar mass of the solute ([tex]\(CNO_3\)[/tex]): 101.1 grams per mole
2. Convert the volume of solution to liters:
- Volume in liters = Volume in milliliters / 1000
- Volume in liters = 300 ml / 1000
- Volume in liters = 0.3 liters
3. Calculate the number of moles of solute:
- Moles of solute = Mass of solute / Molar mass of solute
- Moles of solute = 10 grams / 101.1 grams per mole
- Moles of solute ≈ 0.09891196834817013 moles
4. Calculate the molarity of the solution:
- Molarity (M) = Moles of solute / Volume of solution in liters
- Molarity (M) = 0.09891196834817013 moles / 0.3 liters
- Molarity (M) ≈ 0.3297065611605671 M
Therefore, the molarity of the solution is approximately 0.3297 M.
1. Identify the given values:
- Mass of solute (solute here is [tex]\(K_2O_3\)[/tex]): 10 grams
- Volume of the solution: 300 milliliters
- Molar mass of the solute ([tex]\(CNO_3\)[/tex]): 101.1 grams per mole
2. Convert the volume of solution to liters:
- Volume in liters = Volume in milliliters / 1000
- Volume in liters = 300 ml / 1000
- Volume in liters = 0.3 liters
3. Calculate the number of moles of solute:
- Moles of solute = Mass of solute / Molar mass of solute
- Moles of solute = 10 grams / 101.1 grams per mole
- Moles of solute ≈ 0.09891196834817013 moles
4. Calculate the molarity of the solution:
- Molarity (M) = Moles of solute / Volume of solution in liters
- Molarity (M) = 0.09891196834817013 moles / 0.3 liters
- Molarity (M) ≈ 0.3297065611605671 M
Therefore, the molarity of the solution is approximately 0.3297 M.
Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Find reliable answers at IDNLearn.com. Thanks for stopping by, and come back for more trustworthy solutions.