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How do I simplify (2^1/3)^2-x to get 2^2/3-x/3? that is (2 to the power of 1/3) squared minus x, simplified to 2 to the power of 2/3-x/3. What is the process? How do I simplify these exponents? see screen shot

How Do I Simplify 2132x To Get 223x3 That Is 2 To The Power Of 13 Squared Minus X Simplified To 2 To The Power Of 23x3 What Is The Process How Do I Simplify The class=

Sagot :

Answer: See the below steps for simplifying to [tex]2^{\frac{2}{3}-\frac{x}{3} }[/tex].

Step-by-step explanation:

         We will simplify the given expression to reach the requested result. For this we will use the exponent rules, which I have outlined below.

[tex]\text{Exponent Rules: } \boxed{(x^m)^n=x^{m*n}}\;\;\boxed{x^mx^n=x^{m+n}}\;\;\boxed{\frac{x^m}{x^n}=x^{m-n} }\;\; \boxed{x^{-m}=\frac{1}{x^m} }[/tex]

Given:

    [tex]\displaystyle (2^{\frac{1}{3} })^{2-x}[/tex]

Apply the power to a power rule:

[tex]\boxed{(x^m)^n=x^{m*n}}[/tex]

    [tex]\displaystyle 2^{(\frac{1}{3}*(2-x) )}[/tex]

Distribute the one-third:

    [tex]\displaystyle 2^{\dfrac{2}{3}-\dfrac{x}{3} }[/tex]