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What is the solution to the equation [tex]\sqrt{2n + 28} - 4\sqrt{n} = 0[/tex]?

A. [tex]n = 2[/tex]
B. [tex]n = 4[/tex]
C. [tex]n = 7[/tex]
D. [tex]n = 14[/tex]


Sagot :

Let's solve the equation step-by-step: [tex]\(\sqrt{2n + 28} - 4\sqrt{n} = 0\)[/tex].

1. We start with the given equation:
[tex]\[ \sqrt{2n + 28} - 4\sqrt{n} = 0 \][/tex]

2. To isolate [tex]\(\sqrt{2n + 28}\)[/tex], let’s make [tex]\(\sqrt{2n + 28}\)[/tex] equal to [tex]\(4\sqrt{n}\)[/tex]:
[tex]\[ \sqrt{2n + 28} = 4\sqrt{n} \][/tex]

3. Now, we square both sides of the equation to remove the square roots:
[tex]\[ (\sqrt{2n + 28})^2 = (4\sqrt{n})^2 \][/tex]

Simplifying this, we get:
[tex]\[ 2n + 28 = 16n \][/tex]

4. We need to solve for [tex]\(n\)[/tex]. Let’s isolate [tex]\(n\)[/tex] on one side of the equation:
[tex]\[ 2n + 28 = 16n \][/tex]

Subtract [tex]\(2n\)[/tex] from both sides:
[tex]\[ 28 = 14n \][/tex]

5. Finally, divide both sides by 14:
[tex]\[ n = \frac{28}{14} \][/tex]
[tex]\[ n = 2 \][/tex]

So, the solution to the equation [tex]\(\sqrt{2n + 28} - 4\sqrt{n} = 0\)[/tex] is [tex]\( n = 2 \)[/tex]. Therefore, from the given options, [tex]\( n = 2 \)[/tex] is the correct answer.