Engage with knowledgeable experts and get accurate answers on IDNLearn.com. Whether it's a simple query or a complex problem, our community has the answers you need.

Solve [tex]10 + 6(-9 - 4x) = 10(x - 12) + 8[/tex].

A. [tex]x = -18[/tex]
B. [tex]x = 2[/tex]
C. [tex]x = 17[/tex]
D. [tex]x = -6[/tex]


Sagot :

To solve the equation [tex]\(10 + 6(-9 - 4x) = 10(x - 12) + 8\)[/tex], let's go through the steps methodically.

1. Expand and simplify both sides of the equation:

Start by distributing and simplifying each term:
[tex]\[ 10 + 6(-9 - 4x) = 10(x - 12) + 8 \][/tex]

For the left-hand side (LHS):
[tex]\[ 6(-9 - 4x) = 6(-9) + 6(-4x) = -54 - 24x \][/tex]
Thus,
[tex]\[ 10 + (-54 - 24x) = 10 - 54 - 24x = -44 - 24x \][/tex]

For the right-hand side (RHS):
[tex]\[ 10(x - 12) = 10x - 120 \][/tex]
Thus,
[tex]\[ 10x - 120 + 8 = 10x - 112 \][/tex]

Now the equation is:
[tex]\[ -44 - 24x = 10x - 112 \][/tex]

2. Combine like terms to solve for [tex]\(x\)[/tex]:

To isolate [tex]\(x\)[/tex], first add [tex]\(24x\)[/tex] to both sides of the equation:
[tex]\[ -44 - 24x + 24x = 10x - 112 + 24x \][/tex]
This simplifies to:
[tex]\[ -44 = 34x - 112 \][/tex]

Next, add 112 to both sides:
[tex]\[ -44 + 112 = 34x - 112 + 112 \][/tex]
This simplifies to:
[tex]\[ 68 = 34x \][/tex]

Finally, divide both sides by 34:
[tex]\[ \frac{68}{34} = x \][/tex]
Simplifies to:
[tex]\[ 2 = x \text{ or } x = 2 \][/tex]

3. Verification:

To confirm the solution, substitute [tex]\( x = 2 \)[/tex] back into the original equation:

LHS:
[tex]\[ 10 + 6(-9 - 4 \cdot 2) = 10 + 6(-9 - 8) = 10 + 6(-17) = 10 - 102 = -92 \][/tex]

RHS:
[tex]\[ 10(2 - 12) + 8 = 10(-10) + 8 = -100 + 8 = -92 \][/tex]

Since both sides equal [tex]\(-92\)[/tex], the solution [tex]\( x = 2 \)[/tex] is correct.

Therefore, the correct answer is:
[tex]\[ \boxed{x = 2} \][/tex]

So, the solution to the equation [tex]\(10 + 6(-9 - 4x) = 10(x - 12) + 8\)[/tex] is:
[tex]\[B. x = 2\][/tex]
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Discover the answers you need at IDNLearn.com. Thank you for visiting, and we hope to see you again for more solutions.