IDNLearn.com: Your destination for reliable and timely answers to any question. Discover the information you need quickly and easily with our reliable and thorough Q&A platform.
Sagot :
To determine which factoring method can be considered for the polynomial [tex]\( 3x^3 + 5x + 6x^2 + 10 \)[/tex], it is essential to explore each factoring method:
1. Perfect-Square Trinomial: This method is applicable if the polynomial is of the form [tex]\( a^2x^2 + 2abx + b^2 \)[/tex]. Our polynomial has four terms, not in the form of a perfect-square trinomial. Therefore, this method is not applicable.
2. Difference of Squares: This method applies to polynomials of the form [tex]\( a^2 - b^2 \)[/tex]. Our polynomial does not fit this form, as it is not a binomial and does not represent a difference between two squares. Thus, this method is also not applicable.
3. Factor by Grouping: This technique involves grouping terms in pairs, factoring out the greatest common factor (GCF) from each pair, and then looking for a common factor in the resulting expression. Since our polynomial has four terms, this method could be suitable. We will explore this approach in more detail below.
4. Sum of Cubes: This method is applicable to expressions of the form [tex]\( a^3 + b^3 \)[/tex]. Our polynomial is not in this form, so this method is not applicable.
Factor by Grouping appears to be the most appropriate method for our polynomial [tex]\( 3x^3 + 5x + 6x^2 + 10 \)[/tex].
### Steps for Factor by Grouping
1. Group terms in pairs:
[tex]\[ (3x^3 + 6x^2) + (5x + 10) \][/tex]
2. Factor out the GCF in each pair:
[tex]\[ 3x^2(x + 2) + 5(x + 2) \][/tex]
3. Factor out the common binomial factor ([tex]\(x + 2\)[/tex]):
[tex]\[ (x + 2)(3x^2 + 5) \][/tex]
Thus, upon factoring by grouping, we obtain the factored form of the polynomial:
[tex]\[ (3x^3 + 5x + 6x^2 + 10) = (x + 2)(3x^2 + 5) \][/tex]
So, the factoring method that can be considered for the polynomial [tex]\( 3x^3 + 5x + 6x^2 + 10 \)[/tex] is factor by grouping.
1. Perfect-Square Trinomial: This method is applicable if the polynomial is of the form [tex]\( a^2x^2 + 2abx + b^2 \)[/tex]. Our polynomial has four terms, not in the form of a perfect-square trinomial. Therefore, this method is not applicable.
2. Difference of Squares: This method applies to polynomials of the form [tex]\( a^2 - b^2 \)[/tex]. Our polynomial does not fit this form, as it is not a binomial and does not represent a difference between two squares. Thus, this method is also not applicable.
3. Factor by Grouping: This technique involves grouping terms in pairs, factoring out the greatest common factor (GCF) from each pair, and then looking for a common factor in the resulting expression. Since our polynomial has four terms, this method could be suitable. We will explore this approach in more detail below.
4. Sum of Cubes: This method is applicable to expressions of the form [tex]\( a^3 + b^3 \)[/tex]. Our polynomial is not in this form, so this method is not applicable.
Factor by Grouping appears to be the most appropriate method for our polynomial [tex]\( 3x^3 + 5x + 6x^2 + 10 \)[/tex].
### Steps for Factor by Grouping
1. Group terms in pairs:
[tex]\[ (3x^3 + 6x^2) + (5x + 10) \][/tex]
2. Factor out the GCF in each pair:
[tex]\[ 3x^2(x + 2) + 5(x + 2) \][/tex]
3. Factor out the common binomial factor ([tex]\(x + 2\)[/tex]):
[tex]\[ (x + 2)(3x^2 + 5) \][/tex]
Thus, upon factoring by grouping, we obtain the factored form of the polynomial:
[tex]\[ (3x^3 + 5x + 6x^2 + 10) = (x + 2)(3x^2 + 5) \][/tex]
So, the factoring method that can be considered for the polynomial [tex]\( 3x^3 + 5x + 6x^2 + 10 \)[/tex] is factor by grouping.
We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for trusting IDNLearn.com with your questions. Visit us again for clear, concise, and accurate answers.