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An artificial satellite of the Earth revolves in a circular orbit at a height of 35,900 km above the Earth's surface. What are the orbital speed and the period of revolution of the satellite?

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Final answer:

The answer explains how to calculate the orbital speed and period of revolution of an artificial satellite orbiting the Earth at a specific height, along with information on Clarke's orbit.


Explanation:

Orbital speed: To calculate the orbital speed of a satellite, we use the formula v = √(GM / r), where G is the gravitational constant, M is the mass of the Earth, and r is the distance from the center of the Earth to the satellite. Substituting the values and solving will give you the orbital speed.

Period of revolution: The period of revolution can be calculated using Kepler's third law, which states that T² = (4π²r³) / GM. By substituting the values for r and solving, you can find the period of revolution.

Clarke's orbit: This orbit is named after the author who suggested it, and satellites in this orbit always stay above a specific position on Earth's surface.


Learn more about Calculating orbital speed and period of revolution of satellites here:

https://brainly.com/question/41110639


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