Find expert answers and community support for all your questions on IDNLearn.com. Join our Q&A platform to access reliable and detailed answers from experts in various fields.
Sagot :
To determine the value of [tex]\(q\)[/tex] when given [tex]\(p = 0.22\)[/tex], we use the principle that the sum of the frequencies of the two alleles for a given trait must equal 1. This is because the alleles [tex]\(p\)[/tex] and [tex]\(q\)[/tex] represent the complete set of options for that trait.
Here are the steps to solve the problem:
1. Understand the relationship between [tex]\(p\)[/tex] and [tex]\(q\)[/tex]:
- The sum of the frequencies of the two alleles must be 1.
[tex]\[ p + q = 1 \][/tex]
2. Given value:
- We know [tex]\(p = 0.22\)[/tex].
3. Set up the equation to solve for [tex]\(q\)[/tex]:
[tex]\[ 0.22 + q = 1 \][/tex]
4. Isolate [tex]\(q\)[/tex] by subtracting [tex]\(0.22\)[/tex] from both sides:
[tex]\[ q = 1 - 0.22 \][/tex]
5. Calculate the result:
[tex]\[ q = 0.78 \][/tex]
Thus, the value of [tex]\(q\)[/tex] is [tex]\(\boxed{0.78}\)[/tex].
By analyzing the given answer choices:
A. 0.88
B. 0.78
C. 0.22
D. 0.47
The correct answer is [tex]\( \text{B.} \quad 0.78\)[/tex].
Here are the steps to solve the problem:
1. Understand the relationship between [tex]\(p\)[/tex] and [tex]\(q\)[/tex]:
- The sum of the frequencies of the two alleles must be 1.
[tex]\[ p + q = 1 \][/tex]
2. Given value:
- We know [tex]\(p = 0.22\)[/tex].
3. Set up the equation to solve for [tex]\(q\)[/tex]:
[tex]\[ 0.22 + q = 1 \][/tex]
4. Isolate [tex]\(q\)[/tex] by subtracting [tex]\(0.22\)[/tex] from both sides:
[tex]\[ q = 1 - 0.22 \][/tex]
5. Calculate the result:
[tex]\[ q = 0.78 \][/tex]
Thus, the value of [tex]\(q\)[/tex] is [tex]\(\boxed{0.78}\)[/tex].
By analyzing the given answer choices:
A. 0.88
B. 0.78
C. 0.22
D. 0.47
The correct answer is [tex]\( \text{B.} \quad 0.78\)[/tex].
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.