Certainly! Let's evaluate the function [tex]\( f(x) = x^2 + 2x - 4 \)[/tex] at [tex]\( x = -1 \)[/tex].
We start by substituting [tex]\( x = -1 \)[/tex] into the function:
[tex]\[ f(x) = x^2 + 2x - 4 \][/tex]
[tex]\[ f(-1) = (-1)^2 + 2(-1) - 4 \][/tex]
Now, we'll calculate each term step-by-step:
1. Compute [tex]\( (-1)^2 \)[/tex]:
[tex]\[ (-1)^2 = 1 \][/tex]
2. Compute [tex]\( 2(-1) \)[/tex]:
[tex]\[ 2 \cdot (-1) = -2 \][/tex]
3. Combine all terms:
[tex]\[ f(-1) = 1 + (-2) - 4 \][/tex]
[tex]\[ f(-1) = 1 - 2 - 4 \][/tex]
[tex]\[ f(-1) = -1 - 4 \][/tex]
[tex]\[ f(-1) = -5 \][/tex]
Therefore, the value of [tex]\( f(-1) \)[/tex] is [tex]\( -5 \)[/tex].
