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How many neutrons are in an isotope of selenium-83?

Sagot :

To find the number of neutrons in an isotope, you can use the formula:

\[ \text{Number of neutrons} = \text{Mass number} - \text{Atomic number} \]

For selenium-83 (\( ^{83}\text{Se} \)):

- The mass number is 83.

- The atomic number of selenium (Se) is 34.

So, the number of neutrons is:

\[ 83 - 34 = 49 \]

Therefore, selenium-83 has 49 neutrons.

Anymore?