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At 2:30 AM, the temperature in Joelle is [tex]$-3^{\circ} F$[/tex]. The temperature drops [tex]$\frac{3}{4}$[/tex] of a degree in 30 minutes. What is the temperature in Joelle at 3:00 AM?

A. [tex]-4. \overline{3}^{\circ} F[/tex]
B. [tex]-3.75^{\circ} F[/tex]
C. [tex]-2.25^{\circ} F[/tex]
D. [tex]-1. \overline{6}^{\circ} F[/tex]


Sagot :

To find the temperature in Joelle at 3:00 AM given that the temperature at 2:30 AM is [tex]\(-3^{\circ} F\)[/tex] and it drops [tex]\(\frac{3}{4}\)[/tex] of a degree in 30 minutes, follow these steps:

1. Identify the initial temperature:
- The initial temperature at 2:30 AM is [tex]\(-3^{\circ} F\)[/tex].

2. Determine the change in temperature:
- The temperature drops by [tex]\(\frac{3}{4}\)[/tex] of a degree in 30 minutes.

3. Calculate the new temperature:
- Subtract the temperature drop from the initial temperature.
- New temperature = Initial temperature [tex]\(-\)[/tex] Temperature drop

4. Apply the values:
- Initial temperature = [tex]\(-3^{\circ} F\)[/tex]
- Temperature drop = [tex]\(\frac{3}{4}\)[/tex]

New temperature = [tex]\(-3\)[/tex] - [tex]\(\frac{3}{4}\)[/tex]

5. Convert the temperature drop to a decimal for easier subtraction:
- [tex]\(\frac{3}{4} = 0.75\)[/tex]

So, New temperature = [tex]\(-3 - 0.75 = -3.75^{\circ} F\)[/tex]

Thus, the temperature in Joelle at 3:00 AM is [tex]\(-3.75^{\circ} F\)[/tex].

Therefore, the correct answer is:

[tex]\[ \boxed{-3.75^{\circ} F} \][/tex]