Get clear, concise, and accurate answers to your questions on IDNLearn.com. Find the information you need quickly and easily with our comprehensive and accurate Q&A platform.

[tex]$19.64 \, \text{g} \, \text{H}_2\text{SO}_4$[/tex] dissociates in [tex]$100.0 \, \text{g}$[/tex] of water in a coffee cup calorimeter. The temperature rose from [tex]$23.12^{\circ} \text{C}$[/tex] to [tex]$57.30^{\circ} \text{C}$[/tex]. What is the heat of the reaction, [tex]$q_{\text{rxn}}$[/tex]?

[tex]\[
\begin{aligned}
\text{H}_2\text{SO}_4 & \rightarrow \text{H}^+ + \text{HSO}_4^{-} \\
C_{\text{soln}} & = 3.50 \, \text{J} / \text{g} \, ^{\circ} \text{C} \\
q_{\text{rxn}} & = [?] \, \text{J}
\end{aligned}
\][/tex]

Enter either a + or - sign AND the magnitude.


Sagot :

To determine the heat of the reaction ([tex]\( q_{\text{rxn}} \)[/tex]), we will follow a series of steps to calculate it based on the given data. Here’s a detailed, step-by-step solution:

1. Initial Data:

- Mass of [tex]\( \text{H}_2\text{SO}_4 \)[/tex]: [tex]\( 19.64 \)[/tex] grams
- Mass of water: [tex]\( 100.0 \)[/tex] grams
- Specific heat capacity of the solution ([tex]\( C_{\text{soln}} \)[/tex]): [tex]\( 3.50 \)[/tex] J/g°C
- Initial temperature: [tex]\( 23.12 \)[/tex] °C
- Final temperature: [tex]\( 57.30 \)[/tex] °C

2. Calculate Total Mass of the Solution:

The total mass of the solution is the sum of the mass of [tex]\( \text{H}_2\text{SO}_4 \)[/tex] and the mass of water:

[tex]\[ \text{Total mass of solution} = \text{mass}_{\text{H}_2\text{SO}_4} + \text{mass}_{\text{water}} \][/tex]

[tex]\[ \text{Total mass of solution} = 19.64 \, \text{grams} + 100.0 \, \text{grams} = 119.64 \, \text{grams} \][/tex]

3. Calculate the Change in Temperature ([tex]\( \Delta T \)[/tex]):

[tex]\[ \Delta T = \text{final temperature} - \text{initial temperature} \][/tex]

[tex]\[ \Delta T = 57.30 \, °C - 23.12 \, °C = 34.18 \, °C \][/tex]

4. Calculate the Heat of the Reaction ([tex]\( q_{\text{rxn}} \)[/tex]) Using [tex]\( q = mc\Delta T \)[/tex]:

[tex]\[ q_{\text{rxn}} = \text{total mass of solution} \times \text{specific heat capacity of solution} \times \Delta T \][/tex]

[tex]\[ q_{\text{rxn}} = 119.64 \, \text{grams} \times 3.50 \, \text{J/g°C} \times 34.18 \, °C \][/tex]

[tex]\[ q_{\text{rxn}} = 119.64 \times 3.50 \times 34.18 = 14312.53 \, \text{J} \][/tex]

The heat of the reaction [tex]\( q_{\text{rxn}} \)[/tex] is positive because the temperature of the solution increased, indicating that the reaction is exothermic and heat was released into the surroundings.

Thus, the heat of the reaction is:

[tex]\[ +14312.53 \, \text{J} \][/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.