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Under constant volume conditions, the heat of combustion of benzoic acid, [tex]$HC_7H_5O_2$[/tex], is [tex]$26.38 \, \text{kJ/g}$[/tex]. A [tex][tex]$1.200 \, \text{g}$[/tex][/tex] sample of benzoic acid is burned in a bomb calorimeter. What is the total heat change for the reaction?

[tex]Q = 1.200 \, \text{g} \times \left(-26.38 \, \frac{\text{kJ}}{\text{g}}\right)[/tex]


Sagot :

Sure, let's go through this step by step!

1. Given Information:
- The heat of combustion of benzoic acid is [tex]\( 26.38 \, \text{kJ/g} \)[/tex].
- The mass of the benzoic acid sample is [tex]\( 1.200 \, \text{g} \)[/tex].

2. Objective:
- We want to determine the total heat change for the reaction when the sample of benzoic acid is burned in a bomb calorimeter.

3. Understanding Heat of Combustion:
- The heat of combustion is the amount of heat released when one gram of a substance is completely burned. Since this value is positive, it represents the amount of energy released per gram of benzoic acid combusted.

4. Calculate the Total Heat Change:
- To find the total heat change, we need to multiply the mass of the benzoic acid by the heat of combustion. This will tell us how much energy is released when [tex]\( 1.200 \, \text{g} \)[/tex] of benzoic acid is burned.

Following the provided equation:
[tex]\[ \text{Total heat change} = \left(1.200 \, \text{g} \right) \times \left(26.38 \, \text{kJ/g} \right) \][/tex]

5. Result:
- When you multiply these values together, you obtain:
[tex]\[ \text{Total heat change} = 31.656 \, \text{kJ} \][/tex]

Thus, the total heat change for the reaction when [tex]\( 1.200 \, \text{g} \)[/tex] of benzoic acid is burned in a bomb calorimeter is [tex]\( 31.656 \, \text{kJ} \)[/tex].
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