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The circumference of the second circle is 2 feet longer than
the circumference of the first circle. How many
feet longer
is the radius of the second than
the of the first?
a.1/2pie
b.1/pie
c.2pie
3.pie
please help me solve this problem


Sagot :

Answer:

b. 1/pi

Step-by-step explanation:

the circumference of a circle :

2pi×r

we have r1 (radius of the first circle) and r2 (radius of the second circle) .

2pi×r2 = 2pi×r1 + 2

r2 = (2pi×r1 + 2)/(2pi) = (pi×r1 + 1)/pi = r1 + 1/pi

so, we see r2 is 1/pi longer than r1.