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List all of the integer values that [tex]\( x \)[/tex] could take to satisfy the following inequality:

[tex]\[ -1.7 \leq x \ \textless \ 1 \][/tex]


Sagot :

To solve the inequality [tex]\(-1.7 \leq x < 1\)[/tex] and find all the integer values that [tex]\(x\)[/tex] can take, let’s break it down step by step:

1. Identify the bounds of the inequality:
- The lower bound is [tex]\(-1.7\)[/tex]
- The upper bound is [tex]\(1\)[/tex]

2. Determine the range of integers within these bounds:
- An integer is a whole number, so we need to find whole numbers that lie within [tex]\(-1.7\)[/tex] and [tex]\(1\)[/tex].

3. Consider the lower bound [tex]\(-1.7\)[/tex]:
- Since [tex]\(-1.7\)[/tex] is not an integer, we look at the next integer greater than [tex]\(-1.7\)[/tex], which is [tex]\(-1\)[/tex].
- [tex]\(\-1\)[/tex] is greater than [tex]\(-1.7\)[/tex] and is within the allowed range.

4. Consider the upper bound [tex]\(1\)[/tex]:
- The inequality is strict on the upper side, meaning [tex]\(x\)[/tex] must be less than [tex]\(1\)[/tex] but not equal to [tex]\(1\)[/tex].
- The largest integer that is less than [tex]\(1\)[/tex] is [tex]\(0\)[/tex].

5. Collect all integers between [tex]\(-1.7\)[/tex] (inclusive) and [tex]\(1\)[/tex] (exclusive):
- The integers within the interval [tex]\(-1\)[/tex] to [tex]\(1\)[/tex] (exclusive) are [tex]\(-1\)[/tex] and [tex]\(0\)[/tex].

6. Final conclusion:
- The integer values that satisfy the inequality [tex]\(-1.7 \leq x < 1\)[/tex] are [tex]\(-1\)[/tex] and [tex]\(0\)[/tex].

Therefore, the integer values that [tex]\(x\)[/tex] can take are [tex]\(-1\)[/tex] and [tex]\(0\)[/tex].