From personal advice to professional guidance, IDNLearn.com has the answers you seek. Our platform provides accurate, detailed responses to help you navigate any topic with ease.

What is this expression in simplest form?

[tex] \frac{x+2}{4x^2+5x+1} \cdot \frac{4x+1}{x^2-4} [/tex]

A. [tex] \frac{1}{(x+1)(x-2)} [/tex]
B. [tex] \frac{x}{(x-2)} [/tex]
C. [tex] \frac{4x+1}{(x+1)(x-2)} [/tex]
D. [tex] \frac{4x+1}{x-2} [/tex]


Sagot :

To simplify the given expression:

[tex]\[ \frac{x+2}{4 x^2+5 x+1} \cdot \frac{4 x+1}{x^2-4} \][/tex]

we should follow these steps:

1. Factor the Denominators:

First, we factor the denominators if possible.

For [tex]\(4 x^2 + 5 x + 1\)[/tex]:
We try to factor it as [tex]\((ax + b)(cx + d)\)[/tex]. We recognize it can be factored as:
[tex]\[ 4 x^2 + 5 x + 1 = (4 x + 1)(x + 1) \][/tex]

For [tex]\(x^2 - 4\)[/tex]:
Recognize it as a difference of squares:
[tex]\[ x^2 - 4 = (x - 2)(x + 2) \][/tex]

2. Rewrite the Expression:

Replace the factored forms in the original expression:
[tex]\[ \frac{x+2}{(4x+1)(x+1)} \cdot \frac{4x+1}{(x-2)(x+2)} \][/tex]

3. Simplify by Canceling Common Factors:

We notice that [tex]\((x+2)\)[/tex] and [tex]\((4x+1)\)[/tex] appear in both numerator and denominator, so they cancel out:
[tex]\[ \frac{\cancel{x+2}}{(4x+1)(x+1)} \cdot \frac{\cancel{4x+1}}{(x-2)\cancel{(x+2)}} \][/tex]

4. Simplified Form:

After canceling common factors, we get:
[tex]\[ \frac{1}{(x+1)(x-2)} \][/tex]

5. Match with Given Choices:

The simplified expression [tex]\(\frac{1}{(x+1)(x-2)}\)[/tex] matches option A.

Thus, the simplest form of the given expression is:

[tex]\[ \boxed{\frac{1}{(x+1)(x-2)}} \][/tex]
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! Your search for answers ends at IDNLearn.com. Thanks for visiting, and we look forward to helping you again soon.