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John wants to buy flowers for his grandma. Roses cost [tex]$3 each, and carnations cost $[/tex]2 each. John has a budget of $35.

1. Write an inequality that represents this situation.
2. If John buys 8 carnations, what is the maximum number of roses he can buy?


Sagot :

Sure, let's break this problem down step by step.

1. Define the costs and budget:
- The cost of one rose is [tex]$3. - The cost of one carnation is $[/tex]2.
- John's total budget is [tex]$35. 2. Formulate the inequality: Let \( r \) represent the number of roses and \( c \) represent the number of carnations. The total amount John spends on roses and carnations must be less than or equal to his budget. This can be represented by the inequality: \[ 3r + 2c \leq 35 \] 3. Calculate the cost of the 8 carnations John buys: John buys 8 carnations, so we calculate the total cost of carnations: \[ \text{Cost of 8 carnations} = 8 \times 2 = 16 \text{ dollars} \] 4. Determine the remaining budget after buying carnations: Subtract the amount spent on carnations from the total budget: \[ \text{Remaining budget} = 35 - 16 = 19 \text{ dollars} \] 5. Calculate the maximum number of roses John can buy with the remaining budget: Since each rose costs $[/tex]3, we divide the remaining budget by the cost of one rose:
[tex]\[ \text{Maximum number of roses} = \left\lfloor \frac{19}{3} \right\rfloor = 6 \text{ roses} \][/tex]

Thus, after buying 8 carnations, John can buy a maximum of 6 roses with the remaining budget.