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A water pump with a power of [tex]$3.4 \times 10^2$[/tex] watts lifts water at the rate of [tex]$7.5 \times 10^{-2}$[/tex] meters/second from a water tank. What is the force exerted by the pump on the water?

A. [tex][tex]$1.5 \times 10^3$[/tex][/tex] newtons
B. [tex]$22 \times 10^3$[/tex] newtons
C. [tex]$4.5 \times 10^3$[/tex] newtons
D. [tex][tex]$5.4 \times 10^3$[/tex][/tex] newtons

Sagot :

GinnyAnsweridn
To determine the force exerted by the pump on the water, we can use the relationship between power, force, and velocity. The formula to calculate force is:

[tex]\[ \text{Force} = \frac{\text{Power}}{\text{Velocity}} \][/tex]

Given that:
- The power of the pump is [tex]\(3.4 \times 10^2\)[/tex] watts.
- The velocity at which water is lifted is [tex]\(7.5 \times 10^{-2}\)[/tex] meters/second.

Substituting these values into the formula, we get:

[tex]\[ \text{Force} = \frac{3.4 \times 10^2 \text{ watts}}{7.5 \times 10^{-2} \text{ m/s}} \][/tex]

When you compute this value, you find the force:

[tex]\[ \text{Force} = 4533.333333333334 \text{ newtons} \][/tex]

So the correct answer is option C.

[tex]\[ \boxed{4.5 \times 10^3} \text{ newtons} \][/tex]
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