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To determine the momentum of a van with a mass of [tex]\(1.5 \times 10^3\)[/tex] kilograms and a velocity of 32 meters per second, we use the formula for momentum:
[tex]\[ \text{Momentum} = \text{Mass} \times \text{Velocity} \][/tex]
Substitute the given values:
[tex]\[ \text{Momentum} = 1.5 \times 10^3 \, \text{kg} \times 32 \, \text{m/s} \][/tex]
Perform the multiplication:
[tex]\[ \text{Momentum} = (1.5 \times 32) \times 10^3 \][/tex]
Calculating [tex]\(1.5 \times 32\)[/tex] gives:
[tex]\[ 1.5 \times 32 = 48 \][/tex]
So,
[tex]\[ \text{Momentum} = 48 \times 10^3 \, \text{kg} \cdot \text{m/s} \][/tex]
This can be written as:
[tex]\[ \text{Momentum} = 4.8 \times 10^4 \, \text{kg} \cdot \text{m/s} \][/tex]
The correct answer is:
D. [tex]\(4.85 \times 10^4\)[/tex] kilogram meters/second
However, the exact calculation without any rounding should be:
[tex]\[ \text{Momentum} = 48000 \, \text{kg} \cdot \text{m/s} \][/tex]
And matching this with the closest value, the final correct answer is:
D. [tex]\( 4.85 \times 10^4 \)[/tex] kilogram meters/second
[tex]\[ \text{Momentum} = \text{Mass} \times \text{Velocity} \][/tex]
Substitute the given values:
[tex]\[ \text{Momentum} = 1.5 \times 10^3 \, \text{kg} \times 32 \, \text{m/s} \][/tex]
Perform the multiplication:
[tex]\[ \text{Momentum} = (1.5 \times 32) \times 10^3 \][/tex]
Calculating [tex]\(1.5 \times 32\)[/tex] gives:
[tex]\[ 1.5 \times 32 = 48 \][/tex]
So,
[tex]\[ \text{Momentum} = 48 \times 10^3 \, \text{kg} \cdot \text{m/s} \][/tex]
This can be written as:
[tex]\[ \text{Momentum} = 4.8 \times 10^4 \, \text{kg} \cdot \text{m/s} \][/tex]
The correct answer is:
D. [tex]\(4.85 \times 10^4\)[/tex] kilogram meters/second
However, the exact calculation without any rounding should be:
[tex]\[ \text{Momentum} = 48000 \, \text{kg} \cdot \text{m/s} \][/tex]
And matching this with the closest value, the final correct answer is:
D. [tex]\( 4.85 \times 10^4 \)[/tex] kilogram meters/second
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