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Which of the following steps would you perform to the system of equations below so that the equations have equal [tex]$x$[/tex]-coefficients?

[tex]
\begin{array}{l}
4x + 2y = 4 \\
8x - y = 18
\end{array}
[/tex]

A. Divide both sides of the top equation by 2

B. Multiply both sides of the top equation by 4

C. Divide both sides of the top equation by 4

D. Multiply both sides of the top equation by 2


Sagot :

To determine which step to perform on the system of equations so that both equations have equal [tex]\(x\)[/tex]-coefficients, follow these steps:

Given:
[tex]\[ \begin{array}{l} 4x + 2y = 4 \\ 8x - y = 18 \end{array} \][/tex]

1. Identify the [tex]\(x\)[/tex]-coefficients in both equations:
- The [tex]\(x\)[/tex]-coefficient in the first equation is [tex]\(4\)[/tex].
- The [tex]\(x\)[/tex]-coefficient in the second equation is [tex]\(8\)[/tex].

2. To make the [tex]\(x\)[/tex]-coefficients equal in both equations, we need to adjust the coefficient [tex]\(4\)[/tex] in the first equation to match the coefficient [tex]\(8\)[/tex] in the second equation.

3. To do this, determine the factor by which you need to multiply the coefficient [tex]\(4\)[/tex] so that it becomes [tex]\(8\)[/tex]. The factor is:
[tex]\[\frac{8}{4} = 2\][/tex]

4. Therefore, we need to multiply both sides of the first equation by [tex]\(2\)[/tex]:
[tex]\[2 \times (4x + 2y) = 2 \times 4\][/tex]
Simplifying, we get:
[tex]\[8x + 4y = 8\][/tex]

Now the new system of equations is:
[tex]\[ \begin{array}{l} 8x + 4y = 8 \\ 8x - y = 18 \end{array} \][/tex]

As we can see, the [tex]\(x\)[/tex]-coefficients in both equations are now equal ([tex]\(8\)[/tex]).

The correct step to perform is to multiply both sides of the top equation by [tex]\(2\)[/tex]. Therefore, the correct option is:

D. Multiply both sides of the top equation by 2