IDNLearn.com is designed to help you find reliable answers quickly and easily. Discover reliable and timely information on any topic from our network of knowledgeable professionals.
Sagot :
Sure, let's analyze each set of pairs to determine whether they represent a function. As a reminder, a relation is considered a function if each [tex]\( x \)[/tex]-value in the relation is paired with exactly one [tex]\( y \)[/tex]-value.
1. First Table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -5 & 10 \\ \hline -3 & 5 \\ \hline -3 & 4 \\ \hline 0 & 0 \\ \hline 5 & -10 \\ \hline \end{array} \][/tex]
- Here, we have the [tex]\( x \)[/tex]-values: [tex]\(-5, -3, -3, 0, 5\)[/tex].
- Notice that the [tex]\( x \)[/tex]-value [tex]\(-3\)[/tex] is repeated, but paired with different [tex]\( y \)[/tex]-values [tex]\(5\)[/tex] and [tex]\(4\)[/tex].
- Since [tex]\(-3\)[/tex] is associated with two different [tex]\( y \)[/tex]-values, the first table does not represent a function.
2. Second Table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -2 & -3 \\ \hline -1 & -2 \\ \hline 0 & -1 \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline \end{array} \][/tex]
- Here, we have the [tex]\( x \)[/tex]-values: [tex]\(-2, -1, 0, 0, 1\)[/tex].
- Notice that the [tex]\( x \)[/tex]-value [tex]\(0\)[/tex] is repeated, but paired with different [tex]\( y \)[/tex]-values [tex]\(-1\)[/tex] and [tex]\(0\)[/tex].
- Since [tex]\(0\)[/tex] is associated with two different [tex]\( y \)[/tex]-values, the second table does not represent a function.
3. Set of Pairs:
[tex]\[ \{(-12, 4), (-6, 10), (-4, 15), (-8, 18), (-12, 24)\} \][/tex]
- Here, we have the [tex]\( x \)[/tex]-values: [tex]\(-12, -6, -4, -8, -12\)[/tex].
- Notice that the [tex]\( x \)[/tex]-value [tex]\(-12\)[/tex] is repeated, but paired with different [tex]\( y \)[/tex]-values [tex]\(4\)[/tex] and [tex]\(24\)[/tex].
- Since [tex]\(-12\)[/tex] is associated with two different [tex]\( y \)[/tex]-values, this set does not represent a function.
Therefore, none of the given tables or sets represent a function since each has at least one [tex]\( x \)[/tex]-value associated with more than one [tex]\( y \)[/tex]-value.
1. First Table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -5 & 10 \\ \hline -3 & 5 \\ \hline -3 & 4 \\ \hline 0 & 0 \\ \hline 5 & -10 \\ \hline \end{array} \][/tex]
- Here, we have the [tex]\( x \)[/tex]-values: [tex]\(-5, -3, -3, 0, 5\)[/tex].
- Notice that the [tex]\( x \)[/tex]-value [tex]\(-3\)[/tex] is repeated, but paired with different [tex]\( y \)[/tex]-values [tex]\(5\)[/tex] and [tex]\(4\)[/tex].
- Since [tex]\(-3\)[/tex] is associated with two different [tex]\( y \)[/tex]-values, the first table does not represent a function.
2. Second Table:
[tex]\[ \begin{array}{|c|c|} \hline x & y \\ \hline -2 & -3 \\ \hline -1 & -2 \\ \hline 0 & -1 \\ \hline 0 & 0 \\ \hline 1 & -1 \\ \hline \end{array} \][/tex]
- Here, we have the [tex]\( x \)[/tex]-values: [tex]\(-2, -1, 0, 0, 1\)[/tex].
- Notice that the [tex]\( x \)[/tex]-value [tex]\(0\)[/tex] is repeated, but paired with different [tex]\( y \)[/tex]-values [tex]\(-1\)[/tex] and [tex]\(0\)[/tex].
- Since [tex]\(0\)[/tex] is associated with two different [tex]\( y \)[/tex]-values, the second table does not represent a function.
3. Set of Pairs:
[tex]\[ \{(-12, 4), (-6, 10), (-4, 15), (-8, 18), (-12, 24)\} \][/tex]
- Here, we have the [tex]\( x \)[/tex]-values: [tex]\(-12, -6, -4, -8, -12\)[/tex].
- Notice that the [tex]\( x \)[/tex]-value [tex]\(-12\)[/tex] is repeated, but paired with different [tex]\( y \)[/tex]-values [tex]\(4\)[/tex] and [tex]\(24\)[/tex].
- Since [tex]\(-12\)[/tex] is associated with two different [tex]\( y \)[/tex]-values, this set does not represent a function.
Therefore, none of the given tables or sets represent a function since each has at least one [tex]\( x \)[/tex]-value associated with more than one [tex]\( y \)[/tex]-value.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Your questions are important to us at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.