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Sagot :
Certainly! Let's calculate the square roots of given perfect squares step by step:
1. [tex]\(\sqrt{16}\)[/tex]
- The square root of 16 is the number which, when multiplied by itself, gives 16. That number is 4.
- Therefore, [tex]\(\sqrt{16} = 4.0\)[/tex].
2. [tex]\(\sqrt{49}\)[/tex]
- The square root of 49 is the number which, when multiplied by itself, gives 49. That number is 7.
- Therefore, [tex]\(\sqrt{49} = 7.0\)[/tex].
3. [tex]\(\sqrt{289}\)[/tex]
- The square root of 289 is the number which, when multiplied by itself, gives 289. That number is 17.
- Therefore, [tex]\(\sqrt{289} = 17.0\)[/tex].
So, the completed list is:
[tex]\[ \begin{aligned} \sqrt{16} & = 4.0 \\ \sqrt{49} & = 7.0 \\ \sqrt{289} & = 17.0 \\ \end{aligned} \][/tex]
1. [tex]\(\sqrt{16}\)[/tex]
- The square root of 16 is the number which, when multiplied by itself, gives 16. That number is 4.
- Therefore, [tex]\(\sqrt{16} = 4.0\)[/tex].
2. [tex]\(\sqrt{49}\)[/tex]
- The square root of 49 is the number which, when multiplied by itself, gives 49. That number is 7.
- Therefore, [tex]\(\sqrt{49} = 7.0\)[/tex].
3. [tex]\(\sqrt{289}\)[/tex]
- The square root of 289 is the number which, when multiplied by itself, gives 289. That number is 17.
- Therefore, [tex]\(\sqrt{289} = 17.0\)[/tex].
So, the completed list is:
[tex]\[ \begin{aligned} \sqrt{16} & = 4.0 \\ \sqrt{49} & = 7.0 \\ \sqrt{289} & = 17.0 \\ \end{aligned} \][/tex]
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