Dive into the world of knowledge and get your queries resolved at IDNLearn.com. Discover comprehensive answers to your questions from our community of knowledgeable experts.

The table below shows four samples of carbon dioxide and the temperature of the water they were dissolved in.

\begin{tabular}{|c|c|}
\hline Sample & Temperature of water [tex]$\left({ }^{\circ} C \right)$[/tex] \\
\hline 1 & 78 \\
\hline 2 & 73 \\
\hline 3 & 55 \\
\hline 4 & 63 \\
\hline
\end{tabular}

Which of the samples most likely had the lowest solubility?

A. Sample 1
B. Sample 2
C. Sample 3
D. Sample 4


Sagot :

To determine which of the samples most likely had the lowest solubility, we need to consider the relationship between temperature and the solubility of gases in water. Specifically, the solubility of a gas in water typically decreases as the temperature increases. Therefore, the sample with the highest temperature will generally have the lowest solubility.

Let's examine the given table of temperatures for each sample:

[tex]\[ \begin{array}{|c|c|} \hline \text{Sample} & \text{Temperature of water} \left({ }^{\circ} C \right) \\ \hline 1 & 78 \\ \hline 2 & 73 \\ \hline 3 & 55 \\ \hline 4 & 63 \\ \hline \end{array} \][/tex]

By looking at the temperatures:

- Sample 1: 78°C
- Sample 2: 73°C
- Sample 3: 55°C
- Sample 4: 63°C

We can see that Sample 1 has the highest temperature at 78°C. Because solubility decreases with increasing temperature, Sample 1 is most likely to have the lowest solubility.

Therefore, the sample most likely to have the lowest solubility is Sample 1.