Bridget28chipfikoidn
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Find the equation of the line that has a slope of [tex]$m = \frac{1}{4}$[/tex] and a [tex]$y$[/tex]-intercept of 2.

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GinnyAnsweridn
To find the equation of a line with a given slope and y-intercept, we can use the slope-intercept form of the equation of a line, which is:

[tex]\[ y = mx + b \][/tex]

where:
- [tex]\( m \)[/tex] is the slope of the line.
- [tex]\( b \)[/tex] is the y-intercept, which is the value of [tex]\( y \)[/tex] when [tex]\( x \)[/tex] is 0.

Given:
- The slope [tex]\( m = \frac{1}{4} \)[/tex].
- The y-intercept [tex]\( b = 2 \)[/tex].

Let's substitute these values into the slope-intercept form equation.

[tex]\[ y = \left(\frac{1}{4}\right)x + 2 \][/tex]

So, the equation of the line with a slope of [tex]\(\frac{1}{4}\)[/tex] and a y-intercept of 2 is:

[tex]\[ y = \left(\frac{1}{4}\right)x + 2 \][/tex]

Thus, the equation of the line is:
[tex]\[ y = (0.25)x + 2 \][/tex]

This is the required equation of the line.
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