From tech troubles to travel tips, IDNLearn.com has answers to all your questions. Find the information you need quickly and easily with our reliable and thorough Q&A platform.
Sagot :
Let's solve the expression [tex]\(\left(-\frac{3}{4}\right)^{\frac{2}{3}}\)[/tex] step-by-step.
To deal with the fractional exponent of a negative base, we need to consider complex numbers because raising a negative number to a fractional power generally results in a complex number.
Given:
[tex]\[ \left( -\frac{3}{4} \right)^{\frac{2}{3}} \][/tex]
First, let's convert [tex]\(-\frac{3}{4}\)[/tex] into its polar form. The polar form of a complex number [tex]\(r e^{i \theta}\)[/tex] can be useful in evaluating exponents. Here, [tex]\(r\)[/tex] is the magnitude and [tex]\(\theta\)[/tex] is the argument (angle).
1. Calculate the magnitude:
[tex]\[ r = \left| -\frac{3}{4} \right| = \frac{3}{4} \][/tex]
2. Determine the argument:
[tex]\[ \theta = \pi \quad \text{(since the number is negative, its angle with the positive real axis is } \pi \text{ radians)} \][/tex]
Now, express [tex]\(-\frac{3}{4}\)[/tex] in its polar form:
[tex]\[ -\frac{3}{4} = \frac{3}{4} e^{i \pi} \][/tex]
Now we need to raise this to the power of [tex]\(\frac{2}{3}\)[/tex]:
[tex]\[ \left( \frac{3}{4} e^{i \pi} \right)^{\frac{2}{3}} \][/tex]
Using properties of exponents in polar form:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} e^{i \pi \cdot \frac{2}{3}} \][/tex]
3. Calculate the magnitude part:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \][/tex]
4. Compute the argument part:
[tex]\[ e^{i \cdot \frac{2}{3} \pi} \][/tex]
Putting it all together:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \cdot e^{i \cdot \frac{2}{3} \pi} \][/tex]
Evaluate the magnitude:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \approx 0.641 \][/tex]
Evaluate the argument:
[tex]\[ e^{i \cdot \frac{2}{3} \pi} = \cos \left( \frac{2}{3} \pi \right) + i \sin \left( \frac{2}{3} \pi \right) \][/tex]
Using the values of [tex]\(\cos \left( \frac{2}{3} \pi \right)\)[/tex] and [tex]\(\sin \left( \frac{2}{3} \pi \right)\)[/tex]:
[tex]\[ \cos \left( \frac{2}{3} \pi \right) \approx -0.5 \quad \text{and} \quad \sin \left( \frac{2}{3} \pi \right) \approx 0.866 \][/tex]
Thus:
[tex]\[ e^{i \cdot \frac{2}{3} \pi} \approx -0.5 + 0.866i \][/tex]
Combining both parts:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \cdot \left( -0.5 + 0.866i \right) \][/tex]
The final result is:
[tex]\[ (-0.4127409061118282 + 0.7148882197477024i) \][/tex]
So, the result of [tex]\(\left( -\frac{3}{4} \right)^{\frac{2}{3}}\)[/tex] is:
[tex]\[ \boxed{(-0.4127409061118282 + 0.7148882197477024i)} \][/tex]
To deal with the fractional exponent of a negative base, we need to consider complex numbers because raising a negative number to a fractional power generally results in a complex number.
Given:
[tex]\[ \left( -\frac{3}{4} \right)^{\frac{2}{3}} \][/tex]
First, let's convert [tex]\(-\frac{3}{4}\)[/tex] into its polar form. The polar form of a complex number [tex]\(r e^{i \theta}\)[/tex] can be useful in evaluating exponents. Here, [tex]\(r\)[/tex] is the magnitude and [tex]\(\theta\)[/tex] is the argument (angle).
1. Calculate the magnitude:
[tex]\[ r = \left| -\frac{3}{4} \right| = \frac{3}{4} \][/tex]
2. Determine the argument:
[tex]\[ \theta = \pi \quad \text{(since the number is negative, its angle with the positive real axis is } \pi \text{ radians)} \][/tex]
Now, express [tex]\(-\frac{3}{4}\)[/tex] in its polar form:
[tex]\[ -\frac{3}{4} = \frac{3}{4} e^{i \pi} \][/tex]
Now we need to raise this to the power of [tex]\(\frac{2}{3}\)[/tex]:
[tex]\[ \left( \frac{3}{4} e^{i \pi} \right)^{\frac{2}{3}} \][/tex]
Using properties of exponents in polar form:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} e^{i \pi \cdot \frac{2}{3}} \][/tex]
3. Calculate the magnitude part:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \][/tex]
4. Compute the argument part:
[tex]\[ e^{i \cdot \frac{2}{3} \pi} \][/tex]
Putting it all together:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \cdot e^{i \cdot \frac{2}{3} \pi} \][/tex]
Evaluate the magnitude:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \approx 0.641 \][/tex]
Evaluate the argument:
[tex]\[ e^{i \cdot \frac{2}{3} \pi} = \cos \left( \frac{2}{3} \pi \right) + i \sin \left( \frac{2}{3} \pi \right) \][/tex]
Using the values of [tex]\(\cos \left( \frac{2}{3} \pi \right)\)[/tex] and [tex]\(\sin \left( \frac{2}{3} \pi \right)\)[/tex]:
[tex]\[ \cos \left( \frac{2}{3} \pi \right) \approx -0.5 \quad \text{and} \quad \sin \left( \frac{2}{3} \pi \right) \approx 0.866 \][/tex]
Thus:
[tex]\[ e^{i \cdot \frac{2}{3} \pi} \approx -0.5 + 0.866i \][/tex]
Combining both parts:
[tex]\[ \left( \frac{3}{4} \right)^{\frac{2}{3}} \cdot \left( -0.5 + 0.866i \right) \][/tex]
The final result is:
[tex]\[ (-0.4127409061118282 + 0.7148882197477024i) \][/tex]
So, the result of [tex]\(\left( -\frac{3}{4} \right)^{\frac{2}{3}}\)[/tex] is:
[tex]\[ \boxed{(-0.4127409061118282 + 0.7148882197477024i)} \][/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.