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Calculate the molarity of the following solutions:

A) 2.00 liters which contain 5.32 moles of hydrogen chloride.

B) 1.50 liters which contain 0.35 moles of potassium hydroxide.

Sagot :

GinnyAnsweridn
To calculate the molarity of a solution, you can use the formula:

[tex]\[ \text{Molarity} (M) = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \][/tex]

Let's use this formula to find the molarity for both solutions:

### Part A:
Given:
- Volume of the solution (V) = 2.00 liters
- Moles of hydrogen chloride ([tex]\(\text{HCl}\)[/tex]) = 5.32 moles

Calculation:
[tex]\[ \text{Molarity of HCl} = \frac{5.32 \text{ moles}}{2.00 \text{ liters}} \][/tex]
[tex]\[ \text{Molarity of HCl} = 2.66 \text{ M} \][/tex]

The molarity of the hydrogen chloride solution is 2.66 M.

### Part B:
Given:
- Volume of the solution (V) = 1.50 liters
- Moles of potassium hydroxide ([tex]\(\text{KOH}\)[/tex]) = 0.35 moles

Calculation:
[tex]\[ \text{Molarity of KOH} = \frac{0.35 \text{ moles}}{1.50 \text{ liters}} \][/tex]
[tex]\[ \text{Molarity of KOH} \approx 0.2333 \text{ M} \][/tex]

The molarity of the potassium hydroxide solution is approximately 0.2333 M.

Hence, the molarity of the solutions are as follows:
- For solution A (hydrogen chloride): 2.66 M
- For solution B (potassium hydroxide): 0.2333 M
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