IDNLearn.com: Where your questions meet expert answers and community support. Get accurate and comprehensive answers from our network of experienced professionals.
Sagot :
To determine the maximum height of the Gateway Arch in St. Louis, we can analyze the given equation for the arch's shape:
[tex]\[ y = -\frac{2}{315}(x+315)(x-315) \][/tex]
This equation models a parabola, where [tex]\(x\)[/tex] and [tex]\(y\)[/tex] are measured in feet. The x-axis represents the ground.
### Step-by-Step Solution:
1. Identify the Form of the Equation:
The given equation is in the quadratic form where it can be rewritten as:
[tex]\[ y = -\frac{2}{315}(x^2 - 315^2) \][/tex]
This is recognized as a standard quadratic (or parabolic) equation in [tex]\(x\)[/tex].
2. Find the Vertex:
For a parabola given in the form [tex]\( y = a(x - h)^2 + k \)[/tex] or its simplified product form as in this case, the vertex and therefore the maximum or minimum point of the parabola is key. Given the symmetry, the vertex for a parabola of this form is found where [tex]\(x = 0\)[/tex].
3. Substitute [tex]\( x = 0 \)[/tex] into the Equation:
Substituting [tex]\( x = 0 \)[/tex] into the given equation will yield the [tex]\( y \)[/tex]-value at this point, which represents the height of the arch at its peak (vertex of the parabola).
[tex]\[ y = -\frac{2}{315} (0 + 315) (0 - 315) \][/tex]
4. Simplify the Expression:
Evaluate the expression step by step:
[tex]\[ y = -\frac{2}{315} (315)(-315) \][/tex]
[tex]\[ y = -\frac{2}{315} \times -99225 \][/tex]
[tex]\[ y = \frac{2}{315} \times 99225 \][/tex]
[tex]\[ y = \frac{198450}{315} \][/tex]
[tex]\[ y = 630 \][/tex]
5. Conclusion:
The height of the Gateway Arch at its peak is:
[tex]\[ y = 630 \text{ feet} \][/tex]
Thus, the maximum height of the Gateway Arch is 630 feet.
[tex]\[ y = -\frac{2}{315}(x+315)(x-315) \][/tex]
This equation models a parabola, where [tex]\(x\)[/tex] and [tex]\(y\)[/tex] are measured in feet. The x-axis represents the ground.
### Step-by-Step Solution:
1. Identify the Form of the Equation:
The given equation is in the quadratic form where it can be rewritten as:
[tex]\[ y = -\frac{2}{315}(x^2 - 315^2) \][/tex]
This is recognized as a standard quadratic (or parabolic) equation in [tex]\(x\)[/tex].
2. Find the Vertex:
For a parabola given in the form [tex]\( y = a(x - h)^2 + k \)[/tex] or its simplified product form as in this case, the vertex and therefore the maximum or minimum point of the parabola is key. Given the symmetry, the vertex for a parabola of this form is found where [tex]\(x = 0\)[/tex].
3. Substitute [tex]\( x = 0 \)[/tex] into the Equation:
Substituting [tex]\( x = 0 \)[/tex] into the given equation will yield the [tex]\( y \)[/tex]-value at this point, which represents the height of the arch at its peak (vertex of the parabola).
[tex]\[ y = -\frac{2}{315} (0 + 315) (0 - 315) \][/tex]
4. Simplify the Expression:
Evaluate the expression step by step:
[tex]\[ y = -\frac{2}{315} (315)(-315) \][/tex]
[tex]\[ y = -\frac{2}{315} \times -99225 \][/tex]
[tex]\[ y = \frac{2}{315} \times 99225 \][/tex]
[tex]\[ y = \frac{198450}{315} \][/tex]
[tex]\[ y = 630 \][/tex]
5. Conclusion:
The height of the Gateway Arch at its peak is:
[tex]\[ y = 630 \text{ feet} \][/tex]
Thus, the maximum height of the Gateway Arch is 630 feet.
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.