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Check whether the value given in the bracket is a solution or not.

(a) [tex]2x + 4 = 15[/tex]
[tex](x = 2)[/tex]

(b) [tex]7x + 15 = 45[/tex]
[tex](x = 5)[/tex]

(c) [tex]7x + 2 = 23[/tex]
[tex](x = 3)[/tex]

(d) [tex]\frac{4x}{5} + 2 = 6[/tex]
[tex](x = 5)[/tex]

(e) [tex]4p - 5 = 16[/tex]
[tex](p = 7)[/tex]

(f) [tex]4p - 5 = 23[/tex]
[tex](p = 7)[/tex]

(g) [tex]2x + 5 = 15[/tex]
[tex](x = 5)[/tex]

(h) [tex]3x - 4 = 16[/tex]
[tex](x = 2)[/tex]

(i) [tex]\frac{2x}{5} + 4 = 10[/tex]
[tex](x = 5)[/tex]

Sagot :

GinnyAnsweridn
Sure, let's verify whether the given values satisfy the equations one by one.

### (a)
Equation: [tex]\( 2x + 4 = 15 \)[/tex]

Given: [tex]\( x = 2 \)[/tex]

[tex]\[ 2(2) + 4 = 4 + 4 = 8 \][/tex]

The left-hand side (LHS) is 8, which does not equal the right-hand side (RHS) of 15.

Result: The value [tex]\( x = 2 \)[/tex] is not a solution to the equation.

### (b)
Equation: [tex]\( 7x + 15 = 45 \)[/tex]

Given: [tex]\( x = 5 \)[/tex]

[tex]\[ 7(5) + 15 = 35 + 15 = 50 \][/tex]

The LHS is 50, which does not equal the RHS of 45.

Result: The value [tex]\( x = 5 \)[/tex] is not a solution to the equation.

### (c)
Equation: [tex]\( 7x + 2 = 23 \)[/tex]

Given: [tex]\( x = 3 \)[/tex]

[tex]\[ 7(3) + 2 = 21 + 2 = 23 \][/tex]

The LHS is 23, which equals the RHS of 23.

Result: The value [tex]\( x = 3 \)[/tex] is a solution to the equation.

### (d)
Equation: [tex]\( \frac{4x}{5} + 2 = 6 \)[/tex]

Given: [tex]\( x = 5 \)[/tex]

[tex]\[ \frac{4(5)}{5} + 2 = \frac{20}{5} + 2 = 4 + 2 = 6 \][/tex]

The LHS is 6, which equals the RHS of 6.

Result: The value [tex]\( x = 5 \)[/tex] is a solution to the equation.

### (e)
Equation: [tex]\( 4p - 5 = 16 \)[/tex]

Given: [tex]\( p = 7 \)[/tex]

[tex]\[ 4(7) - 5 = 28 - 5 = 23 \][/tex]

The LHS is 23, which does not equal the RHS of 16.

Result: The value [tex]\( p = 7 \)[/tex] is not a solution to the equation.

### (f)
Equation: [tex]\( 4p - 5 = 23 \)[/tex]

Given: [tex]\( p = 7 \)[/tex]

[tex]\[ 4(7) - 5 = 28 - 5 = 23 \][/tex]

The LHS is 23, which equals the RHS of 23.

Result: The value [tex]\( p = 7 \)[/tex] is a solution to the equation.

### (g)
Equation: [tex]\( 2x + 5 = 15 \)[/tex]

Given: [tex]\( x = 5 \)[/tex]

[tex]\[ 2(5) + 5 = 10 + 5 = 15 \][/tex]

The LHS is 15, which equals the RHS of 15.

Result: The value [tex]\( x = 5 \)[/tex] is a solution to the equation.

### (h)
Equation: [tex]\( 3x - 4 = 16 \)[/tex]

Given: [tex]\( x = 2 \)[/tex]

[tex]\[ 3(2) - 4 = 6 - 4 = 2 \][/tex]

The LHS is 2, which does not equal the RHS of 16.

Result: The value [tex]\( x = 2 \)[/tex] is not a solution to the equation.

### (i)
Equation: [tex]\( \frac{2x}{5} + 4 = 10 \)[/tex]

Given: [tex]\( x = 5 \)[/tex]

[tex]\[ \frac{2(5)}{5} + 4 = \frac{10}{5} + 4 = 2 + 4 = 6 \][/tex]

The LHS is 6, which does not equal the RHS of 10.

Result: The value [tex]\( x = 5 \)[/tex] is not a solution to the equation.
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