IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Join our Q&A platform to get accurate and thorough answers to all your pressing questions.

Two spheres have surface areas of [tex]100 \pi[/tex] units[tex]\(^2\)[/tex] and [tex]36 \pi[/tex] units[tex]\(^2\)[/tex].

If the volume of the larger sphere is [tex]\frac{500}{3} \pi[/tex] units[tex]\(^3\)[/tex], determine the following measures:

- Scale factor = [tex]\(\square\)[/tex]
- Radius of smaller sphere = [tex]\(\square\)[/tex] units
- Radius of larger sphere = [tex]\(\square\)[/tex] units
- Volume of smaller sphere = [tex]\(\square \pi\)[/tex] units[tex]\(^3\)[/tex]


Sagot :

Let's break down the problem step-by-step.

1. Finding the radii of the spheres:

Given surface areas:
- Surface area of the larger sphere: [tex]\( 100 \pi \)[/tex] units²
- Surface area of the smaller sphere: [tex]\( 36 \pi \)[/tex] units²

The formula for the surface area of a sphere is:
[tex]\[ 4\pi r^2 \][/tex]

From this, we can solve for the radius [tex]\( r \)[/tex] of each sphere.

For the larger sphere:
[tex]\[ 4\pi r_{\text{large}}^2 = 100 \pi \][/tex]
[tex]\[ r_{\text{large}}^2 = \frac{100 \pi}{4 \pi} = 25 \][/tex]
[tex]\[ r_{\text{large}} = \sqrt{25} = 5 \text{ units} \][/tex]

For the smaller sphere:
[tex]\[ 4\pi r_{\text{small}}^2 = 36 \pi \][/tex]
[tex]\[ r_{\text{small}}^2 = \frac{36 \pi}{4 \pi} = 9 \][/tex]
[tex]\[ r_{\text{small}} = \sqrt{9} = 3 \text{ units} \][/tex]

2. Determining the scale factor:

The scale factor is the ratio of the radii of the larger sphere to the smaller sphere.
[tex]\[ \text{Scale factor} = \frac{r_{\text{large}}}{r_{\text{small}}} = \frac{5}{3} \approx 1.667 \][/tex]

3. Finding the volume of the smaller sphere:

Given the volume of the larger sphere:
[tex]\[ \frac{500}{3} \pi \text{ units}^3 \][/tex]

We know the formula for the volume of a sphere is:
[tex]\[ V = \frac{4}{3} \pi r^3 \][/tex]

For the smaller sphere, using its radius [tex]\( r_{\text{small}} = 3 \)[/tex]:
[tex]\[ V_{\text{small}} = \frac{4}{3} \pi r_{\text{small}}^3 \][/tex]
[tex]\[ V_{\text{small}} = \frac{4}{3} \pi (3)^3 = \frac{4}{3} \pi (27) = 36 \pi \text{ units}^3 \][/tex]

So, summarizing the results:
- Radius of the larger sphere: [tex]\( 5 \)[/tex] units
- Radius of the smaller sphere: [tex]\( 3 \)[/tex] units
- Scale factor: [tex]\( 1.667 \)[/tex]
- Volume of the smaller sphere: [tex]\( \approx 113.097 \)[/tex] units³

These are the complete answers required.
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Discover insightful answers at IDNLearn.com. We appreciate your visit and look forward to assisting you again.