IDNLearn.com makes it easy to find accurate answers to your questions. Ask your questions and get detailed, reliable answers from our community of experienced experts.
Sagot :
To find the average atomic mass of an element with isotopes, you follow these steps:
1. Identify the atomic masses and their respective abundances.
- For isotope [tex]\( X-14 \)[/tex]:
- Atomic mass: 14.003 amu
- Abundance: 99.636%
- For isotope [tex]\( X-15 \)[/tex]:
- Atomic mass: 15.000 amu
- Abundance: 0.364%
2. Convert the abundances from percentages to fractions:
[tex]\[ \text{Abundance of } X-14 = \frac{99.636}{100} = 0.99636 \][/tex]
[tex]\[ \text{Abundance of } X-15 = \frac{0.364}{100} = 0.00364 \][/tex]
3. Multiply each atomic mass by its respective fractional abundance to find the contribution of each isotope to the average atomic mass:
[tex]\[ \text{Contribution of } X-14 = 14.003 \times 0.99636 = 13.95194668 \, \text{amu} \][/tex]
[tex]\[ \text{Contribution of } X-15 = 15.000 \times 0.00364 = 0.0546824 \, \text{amu} \][/tex]
4. Add the contributions of the isotopes to find the average atomic mass:
[tex]\[ \text{Average atomic mass} = 13.95194668 + 0.0546824 = 14.00662908 \, \text{amu} \][/tex]
5. Round the result to the nearest thousandth:
[tex]\[ \text{Average atomic mass} \approx 14.007 \, \text{amu} \][/tex]
Hence, the average atomic mass of element [tex]\( X \)[/tex] is [tex]\( 14.007 \, \text{amu} \)[/tex].
1. Identify the atomic masses and their respective abundances.
- For isotope [tex]\( X-14 \)[/tex]:
- Atomic mass: 14.003 amu
- Abundance: 99.636%
- For isotope [tex]\( X-15 \)[/tex]:
- Atomic mass: 15.000 amu
- Abundance: 0.364%
2. Convert the abundances from percentages to fractions:
[tex]\[ \text{Abundance of } X-14 = \frac{99.636}{100} = 0.99636 \][/tex]
[tex]\[ \text{Abundance of } X-15 = \frac{0.364}{100} = 0.00364 \][/tex]
3. Multiply each atomic mass by its respective fractional abundance to find the contribution of each isotope to the average atomic mass:
[tex]\[ \text{Contribution of } X-14 = 14.003 \times 0.99636 = 13.95194668 \, \text{amu} \][/tex]
[tex]\[ \text{Contribution of } X-15 = 15.000 \times 0.00364 = 0.0546824 \, \text{amu} \][/tex]
4. Add the contributions of the isotopes to find the average atomic mass:
[tex]\[ \text{Average atomic mass} = 13.95194668 + 0.0546824 = 14.00662908 \, \text{amu} \][/tex]
5. Round the result to the nearest thousandth:
[tex]\[ \text{Average atomic mass} \approx 14.007 \, \text{amu} \][/tex]
Hence, the average atomic mass of element [tex]\( X \)[/tex] is [tex]\( 14.007 \, \text{amu} \)[/tex].
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Your questions find clarity at IDNLearn.com. Thanks for stopping by, and come back for more dependable solutions.