Dive into the world of knowledge and get your queries resolved at IDNLearn.com. Whether your question is simple or complex, our community is here to provide detailed and trustworthy answers quickly and effectively.
Sagot :
To find the quadratic equation with roots [tex]\(x = 2 + i\)[/tex] and [tex]\(x = 2 - i\)[/tex], follow these steps:
1. Identify the Roots:
The given roots are [tex]\( x = 2 + i \)[/tex] and [tex]\( x = 2 - i \)[/tex].
2. Form the Factors of the Roots:
The quadratic equation with these roots can be formed by setting up the factors:
[tex]\[ (x - (2 + i))(x - (2 - i)) = 0 \][/tex]
3. Simplify the Expression:
Rewrite the expression to distribute and simplify it step-by-step:
[tex]\[ (x - 2 - i)(x - 2 + i) \][/tex]
This can be seen as a product of a sum and difference of terms:
[tex]\[ [(x - 2) - i][(x - 2) + i] \][/tex]
4. Apply the Difference of Squares Formula:
Using the formula [tex]\((a - b)(a + b) = a^2 - b^2\)[/tex] where [tex]\(a = x - 2\)[/tex] and [tex]\(b = i\)[/tex], we get:
[tex]\[ (x - 2)^2 - (i)^2 \][/tex]
Since [tex]\(i^2 = -1\)[/tex]:
[tex]\[ (x - 2)^2 - (-1) \][/tex]
Simplifying this gives:
[tex]\[ (x - 2)^2 + 1 \][/tex]
5. Expand [tex]\((x - 2)^2\)[/tex]:
Expand the binomial:
[tex]\[ (x - 2)^2 = x^2 - 4x + 4 \][/tex]
6. Form the Quadratic Equation:
Substitute back into the equation:
[tex]\[ (x - 2)^2 + 1 = x^2 - 4x + 4 + 1 = x^2 - 4x + 5 \][/tex]
Thus, the quadratic equation with the roots [tex]\(x = 2 + i\)[/tex] and [tex]\(x = 2 - i\)[/tex] is:
[tex]\[ x^2 - 4x + 5 = 0 \][/tex]
So, the correct quadratic equation is:
[tex]\(\boxed{x^2 - 4x + 5 = 0}\)[/tex]
1. Identify the Roots:
The given roots are [tex]\( x = 2 + i \)[/tex] and [tex]\( x = 2 - i \)[/tex].
2. Form the Factors of the Roots:
The quadratic equation with these roots can be formed by setting up the factors:
[tex]\[ (x - (2 + i))(x - (2 - i)) = 0 \][/tex]
3. Simplify the Expression:
Rewrite the expression to distribute and simplify it step-by-step:
[tex]\[ (x - 2 - i)(x - 2 + i) \][/tex]
This can be seen as a product of a sum and difference of terms:
[tex]\[ [(x - 2) - i][(x - 2) + i] \][/tex]
4. Apply the Difference of Squares Formula:
Using the formula [tex]\((a - b)(a + b) = a^2 - b^2\)[/tex] where [tex]\(a = x - 2\)[/tex] and [tex]\(b = i\)[/tex], we get:
[tex]\[ (x - 2)^2 - (i)^2 \][/tex]
Since [tex]\(i^2 = -1\)[/tex]:
[tex]\[ (x - 2)^2 - (-1) \][/tex]
Simplifying this gives:
[tex]\[ (x - 2)^2 + 1 \][/tex]
5. Expand [tex]\((x - 2)^2\)[/tex]:
Expand the binomial:
[tex]\[ (x - 2)^2 = x^2 - 4x + 4 \][/tex]
6. Form the Quadratic Equation:
Substitute back into the equation:
[tex]\[ (x - 2)^2 + 1 = x^2 - 4x + 4 + 1 = x^2 - 4x + 5 \][/tex]
Thus, the quadratic equation with the roots [tex]\(x = 2 + i\)[/tex] and [tex]\(x = 2 - i\)[/tex] is:
[tex]\[ x^2 - 4x + 5 = 0 \][/tex]
So, the correct quadratic equation is:
[tex]\(\boxed{x^2 - 4x + 5 = 0}\)[/tex]
We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.