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Calculate the pressure in pascals exerted by a force of 300 N acting normally on an area of [tex]$30 \, \text{cm}^2$[/tex].

Sagot :

To calculate the pressure in pascal exerted by a force of 300 N acting normally on an area of 30 cm², we need to follow these steps:

1. Convert the area from square centimeters to square meters:
- The area given is 30 cm².
- We know that [tex]\(1 \text{ cm}^2 = 1 \times 10^{-4} \text{ m}^2\)[/tex].
- So, we need to convert 30 cm² to m²:
[tex]\[ 30 \text{ cm}^2 = 30 \times 10^{-4} \text{ m}^2 = 0.003 \text{ m}^2 \][/tex]

2. Calculate the pressure using the formula:
- The formula for pressure [tex]\(P\)[/tex] is given by [tex]\(P = \frac{F}{A}\)[/tex], where [tex]\(F\)[/tex] is the force and [tex]\(A\)[/tex] is the area.
- In this problem, [tex]\(F = 300 \text{ N}\)[/tex] and [tex]\(A = 0.003 \text{ m}^2\)[/tex].
- Substitute the values into the formula:
[tex]\[ P = \frac{300 \text{ N}}{0.003 \text{ m}^2} \][/tex]

3. Perform the division:
- Divide the force by the area:
[tex]\[ P = \frac{300}{0.003} = 100000 \text{ Pa} \][/tex]

Therefore, the pressure exerted by a force of 300 N acting normally on an area of 30 cm² is 100000 Pa.