IDNLearn.com is your go-to platform for finding reliable answers quickly. Our experts provide accurate and detailed responses to help you navigate any topic or issue with confidence.
Sagot :
Sure, let's find each of the compositions step-by-step:
(a) [tex]\( f \circ g \)[/tex]:
[tex]\( f \circ g(x) \)[/tex] means we apply [tex]\( g \)[/tex] first and then apply [tex]\( f \)[/tex] to the result.
Given [tex]\( g(x) = x - 6 \)[/tex]:
1. First apply [tex]\( g \)[/tex]:
[tex]\[ g(x) = x - 6 \][/tex]
2. Now substitute [tex]\( g(x) \)[/tex] into [tex]\( f \)[/tex]:
[tex]\[ f(g(x)) = f(x - 6) \][/tex]
3. Since [tex]\( f(x) = x^2 \)[/tex], replace [tex]\( x \)[/tex] with [tex]\( x - 6 \)[/tex]:
[tex]\[ f(x - 6) = (x - 6)^2 \][/tex]
So,
[tex]\[ f \circ g(x) = (x - 6)^2 \][/tex]
(b) [tex]\( g \circ f \)[/tex]:
[tex]\( g \circ f(x) \)[/tex] means we apply [tex]\( f \)[/tex] first and then apply [tex]\( g \)[/tex] to the result.
Given [tex]\( f(x) = x^2 \)[/tex]:
1. First apply [tex]\( f \)[/tex]:
[tex]\[ f(x) = x^2 \][/tex]
2. Now substitute [tex]\( f(x) \)[/tex] into [tex]\( g \)[/tex]:
[tex]\[ g(f(x)) = g(x^2) \][/tex]
3. Since [tex]\( g(x) = x - 6 \)[/tex], replace [tex]\( x \)[/tex] with [tex]\( x^2 \)[/tex]:
[tex]\[ g(x^2) = x^2 - 6 \][/tex]
So,
[tex]\[ g \circ f(x) = x^2 - 6 \][/tex]
(c) [tex]\( g \circ g \)[/tex]:
[tex]\( g \circ g(x) \)[/tex] means we apply [tex]\( g \)[/tex] first and then apply [tex]\( g \)[/tex] again to the result.
Given [tex]\( g(x) = x - 6 \)[/tex]:
1. First apply [tex]\( g \)[/tex]:
[tex]\[ g(x) = x - 6 \][/tex]
2. Now substitute [tex]\( g(x) \)[/tex] into [tex]\( g \)[/tex]:
[tex]\[ g(g(x)) = g(x - 6) \][/tex]
3. Since [tex]\( g(x) = x - 6 \)[/tex], replace [tex]\( x \)[/tex] with [tex]\( x - 6 \)[/tex]:
[tex]\[ g(x - 6) = (x - 6) - 6 = x - 12 \][/tex]
So,
[tex]\[ g \circ g(x) = x - 12 \][/tex]
Therefore, the detailed solutions are:
(a) [tex]\( f \circ g(x) = (x - 6)^2 \)[/tex]
(b) [tex]\( g \circ f(x) = x^2 - 6 \)[/tex]
(c) [tex]\( g \circ g(x) = x - 12 \)[/tex]
(a) [tex]\( f \circ g \)[/tex]:
[tex]\( f \circ g(x) \)[/tex] means we apply [tex]\( g \)[/tex] first and then apply [tex]\( f \)[/tex] to the result.
Given [tex]\( g(x) = x - 6 \)[/tex]:
1. First apply [tex]\( g \)[/tex]:
[tex]\[ g(x) = x - 6 \][/tex]
2. Now substitute [tex]\( g(x) \)[/tex] into [tex]\( f \)[/tex]:
[tex]\[ f(g(x)) = f(x - 6) \][/tex]
3. Since [tex]\( f(x) = x^2 \)[/tex], replace [tex]\( x \)[/tex] with [tex]\( x - 6 \)[/tex]:
[tex]\[ f(x - 6) = (x - 6)^2 \][/tex]
So,
[tex]\[ f \circ g(x) = (x - 6)^2 \][/tex]
(b) [tex]\( g \circ f \)[/tex]:
[tex]\( g \circ f(x) \)[/tex] means we apply [tex]\( f \)[/tex] first and then apply [tex]\( g \)[/tex] to the result.
Given [tex]\( f(x) = x^2 \)[/tex]:
1. First apply [tex]\( f \)[/tex]:
[tex]\[ f(x) = x^2 \][/tex]
2. Now substitute [tex]\( f(x) \)[/tex] into [tex]\( g \)[/tex]:
[tex]\[ g(f(x)) = g(x^2) \][/tex]
3. Since [tex]\( g(x) = x - 6 \)[/tex], replace [tex]\( x \)[/tex] with [tex]\( x^2 \)[/tex]:
[tex]\[ g(x^2) = x^2 - 6 \][/tex]
So,
[tex]\[ g \circ f(x) = x^2 - 6 \][/tex]
(c) [tex]\( g \circ g \)[/tex]:
[tex]\( g \circ g(x) \)[/tex] means we apply [tex]\( g \)[/tex] first and then apply [tex]\( g \)[/tex] again to the result.
Given [tex]\( g(x) = x - 6 \)[/tex]:
1. First apply [tex]\( g \)[/tex]:
[tex]\[ g(x) = x - 6 \][/tex]
2. Now substitute [tex]\( g(x) \)[/tex] into [tex]\( g \)[/tex]:
[tex]\[ g(g(x)) = g(x - 6) \][/tex]
3. Since [tex]\( g(x) = x - 6 \)[/tex], replace [tex]\( x \)[/tex] with [tex]\( x - 6 \)[/tex]:
[tex]\[ g(x - 6) = (x - 6) - 6 = x - 12 \][/tex]
So,
[tex]\[ g \circ g(x) = x - 12 \][/tex]
Therefore, the detailed solutions are:
(a) [tex]\( f \circ g(x) = (x - 6)^2 \)[/tex]
(b) [tex]\( g \circ f(x) = x^2 - 6 \)[/tex]
(c) [tex]\( g \circ g(x) = x - 12 \)[/tex]
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.