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A moment of force about a pivot is 20 Nm. If a force of [tex]$5 N$[/tex] is applied, what will be the distance of the force from the pivot?

Sagot :

To solve this problem, let's understand the relationship between torque (also known as the moment of force), force, and the distance from the pivot. The formula that relates these quantities is:

[tex]\[ \text{Torque} (T) = \text{Force} (F) \times \text{Distance} (r) \][/tex]

Given:
- Torque [tex]\( T = 20 \)[/tex] Nm
- Force [tex]\( F = 0 \)[/tex] N

We need to determine the distance [tex]\( r \)[/tex] from the pivot. The formula can be rearranged to solve for [tex]\( r \)[/tex]:

[tex]\[ r = \frac{T}{F} \][/tex]

Substituting the given values:

[tex]\[ r = \frac{20 \, \text{Nm}}{0 \, \text{N}} \][/tex]

However, when we look at this calculation, we notice a significant issue. Dividing by zero is undefined in mathematics because it does not yield a finite or meaningful result. Therefore, the distance [tex]\( r \)[/tex] cannot be determined because you cannot divide by zero.

In conclusion, the distance cannot be determined because the force applied is zero, making the division by zero impossible.
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