IDNLearn.com offers a collaborative platform for sharing and gaining knowledge. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.
Sagot :
To find the length of segment [tex]\(A'B'\)[/tex] after scaling down the quadrilateral with a scale factor of [tex]\(\frac{1}{4}\)[/tex], we need to follow these steps:
1. Identify the coordinates of points A and B:
- [tex]\(A(0,4)\)[/tex]
- [tex]\(B(8,4)\)[/tex]
2. Calculate the original length of segment [tex]\(AB\)[/tex]:
- Using the distance formula for two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex], the distance [tex]\(d\)[/tex] is given by:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
- Plugging in the coordinates of [tex]\(A\)[/tex] and [tex]\(B\)[/tex]:
[tex]\[ AB = \sqrt{(8 - 0)^2 + (4 - 4)^2} \][/tex]
[tex]\[ AB = \sqrt{8^2 + 0^2} \][/tex]
[tex]\[ AB = \sqrt{64} \][/tex]
[tex]\[ AB = 8 \][/tex]
3. Apply the scale factor [tex]\(\frac{1}{4}\)[/tex]:
- The length of [tex]\(A'B'\)[/tex] after applying the scale factor is:
[tex]\[ A'B' = AB \times \frac{1}{4} \][/tex]
- Substituting the length of [tex]\(AB\)[/tex]:
[tex]\[ A'B' = 8 \times \frac{1}{4} \][/tex]
[tex]\[ A'B' = 2 \][/tex]
Thus, the length of segment [tex]\(A'B'\)[/tex] after scaling is [tex]\(2\)[/tex].
Therefore, the correct answer is:
[tex]\[ \boxed{2} \][/tex]
1. Identify the coordinates of points A and B:
- [tex]\(A(0,4)\)[/tex]
- [tex]\(B(8,4)\)[/tex]
2. Calculate the original length of segment [tex]\(AB\)[/tex]:
- Using the distance formula for two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex], the distance [tex]\(d\)[/tex] is given by:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
- Plugging in the coordinates of [tex]\(A\)[/tex] and [tex]\(B\)[/tex]:
[tex]\[ AB = \sqrt{(8 - 0)^2 + (4 - 4)^2} \][/tex]
[tex]\[ AB = \sqrt{8^2 + 0^2} \][/tex]
[tex]\[ AB = \sqrt{64} \][/tex]
[tex]\[ AB = 8 \][/tex]
3. Apply the scale factor [tex]\(\frac{1}{4}\)[/tex]:
- The length of [tex]\(A'B'\)[/tex] after applying the scale factor is:
[tex]\[ A'B' = AB \times \frac{1}{4} \][/tex]
- Substituting the length of [tex]\(AB\)[/tex]:
[tex]\[ A'B' = 8 \times \frac{1}{4} \][/tex]
[tex]\[ A'B' = 2 \][/tex]
Thus, the length of segment [tex]\(A'B'\)[/tex] after scaling is [tex]\(2\)[/tex].
Therefore, the correct answer is:
[tex]\[ \boxed{2} \][/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com provides the best answers to your questions. Thank you for visiting, and come back soon for more helpful information.