Join the conversation on IDNLearn.com and get the answers you seek from experts. Join our Q&A platform to access reliable and detailed answers from experts in various fields.
Sagot :
To determine which ordered pairs satisfy both of the given inequalities:
[tex]\[ \begin{array}{c} y > -3x + 4 \\ y \leq 3x - 2 \end{array} \][/tex]
Let's analyze each ordered pair individually.
1. Ordered pair [tex]\((2,1)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ 1 > -3(2) + 4 \][/tex]
[tex]\[ 1 > -6 + 4 \][/tex]
[tex]\[ 1 > -2 \quad \text{(True)} \][/tex]
- Check the second inequality [tex]\(y \leq 3x - 2\)[/tex]:
[tex]\[ 1 \leq 3(2) - 2 \][/tex]
[tex]\[ 1 \leq 6 - 2 \][/tex]
[tex]\[ 1 \leq 4 \quad \text{(True)} \][/tex]
Both conditions are satisfied for [tex]\((2, 1)\)[/tex].
2. Ordered pair [tex]\((1, -2)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ -2 > -3(1) + 4 \][/tex]
[tex]\[ -2 > -3 + 4 \][/tex]
[tex]\[ -2 > 1 \quad \text{(False)} \][/tex]
Since the first condition is not satisfied, there's no need to check the second condition. [tex]\((1, -2)\)[/tex] is not in the solution set.
3. Ordered pair [tex]\((0, 4)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ 4 > -3(0) + 4 \][/tex]
[tex]\[ 4 > 0 + 4 \][/tex]
[tex]\[ 4 > 4 \quad \text{(False)} \][/tex]
Since the first condition is not satisfied, there's no need to check the second condition. [tex]\((0, 4)\)[/tex] is not in the solution set.
4. Ordered pair [tex]\((1, 3)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ 3 > -3(1) + 4 \][/tex]
[tex]\[ 3 > -3 + 4 \][/tex]
[tex]\[ 3 > 1 \quad \text{(True)} \][/tex]
- Check the second inequality [tex]\(y \leq 3x - 2\)[/tex]:
[tex]\[ 3 \leq 3(1) - 2 \][/tex]
[tex]\[ 3 \leq 3 - 2 \][/tex]
[tex]\[ 3 \leq 1 \quad \text{(False)} \][/tex]
Since the second condition is not satisfied, [tex]\((1, 3)\)[/tex] is not in the solution set.
After analyzing all pairs, the only ordered pair that satisfies both inequalities is [tex]\((2,1)\)[/tex].
Hence, the ordered pair that is in the solution set is [tex]\( (2, 1) \)[/tex].
[tex]\[ \begin{array}{c} y > -3x + 4 \\ y \leq 3x - 2 \end{array} \][/tex]
Let's analyze each ordered pair individually.
1. Ordered pair [tex]\((2,1)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ 1 > -3(2) + 4 \][/tex]
[tex]\[ 1 > -6 + 4 \][/tex]
[tex]\[ 1 > -2 \quad \text{(True)} \][/tex]
- Check the second inequality [tex]\(y \leq 3x - 2\)[/tex]:
[tex]\[ 1 \leq 3(2) - 2 \][/tex]
[tex]\[ 1 \leq 6 - 2 \][/tex]
[tex]\[ 1 \leq 4 \quad \text{(True)} \][/tex]
Both conditions are satisfied for [tex]\((2, 1)\)[/tex].
2. Ordered pair [tex]\((1, -2)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ -2 > -3(1) + 4 \][/tex]
[tex]\[ -2 > -3 + 4 \][/tex]
[tex]\[ -2 > 1 \quad \text{(False)} \][/tex]
Since the first condition is not satisfied, there's no need to check the second condition. [tex]\((1, -2)\)[/tex] is not in the solution set.
3. Ordered pair [tex]\((0, 4)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ 4 > -3(0) + 4 \][/tex]
[tex]\[ 4 > 0 + 4 \][/tex]
[tex]\[ 4 > 4 \quad \text{(False)} \][/tex]
Since the first condition is not satisfied, there's no need to check the second condition. [tex]\((0, 4)\)[/tex] is not in the solution set.
4. Ordered pair [tex]\((1, 3)\)[/tex]:
- Check the first inequality [tex]\(y > -3x + 4\)[/tex]:
[tex]\[ 3 > -3(1) + 4 \][/tex]
[tex]\[ 3 > -3 + 4 \][/tex]
[tex]\[ 3 > 1 \quad \text{(True)} \][/tex]
- Check the second inequality [tex]\(y \leq 3x - 2\)[/tex]:
[tex]\[ 3 \leq 3(1) - 2 \][/tex]
[tex]\[ 3 \leq 3 - 2 \][/tex]
[tex]\[ 3 \leq 1 \quad \text{(False)} \][/tex]
Since the second condition is not satisfied, [tex]\((1, 3)\)[/tex] is not in the solution set.
After analyzing all pairs, the only ordered pair that satisfies both inequalities is [tex]\((2,1)\)[/tex].
Hence, the ordered pair that is in the solution set is [tex]\( (2, 1) \)[/tex].
Your presence in our community is highly appreciated. Keep sharing your insights and solutions. Together, we can build a rich and valuable knowledge resource for everyone. IDNLearn.com is your go-to source for dependable answers. Thank you for visiting, and we hope to assist you again.