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An object that is launched from the top of the tower is dense enough that Air resistance can be ignored. The object initially has a component VX which is equal to 60 m per second VY, which is equal to 20 m per second what are the components of the object velocity 5 second after launch?

Sagot :

Answer:

Explanation:

Vx will not change and will be 60 m/s

Vy WILL change due to gravity

 Vy = Vyi - 9.81 m/s^2 ( t)

      = 20 m/s  - 9.81 ( 5) = -29.05 m/s ( it is coming down)

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