Discover how IDNLearn.com can help you learn and grow with its extensive Q&A platform. Ask any question and get a detailed, reliable answer from our community of experts.
Sagot :
To determine which equation accurately represents the temperature, [tex]\( t \)[/tex], in Burrtown at hour [tex]\( h \)[/tex], let's analyze each option step-by-step based on the given information.
### Given Information:
- The initial temperature at midnight ([tex]\( h = 0 \)[/tex]) is [tex]\( 32^\circ \)[/tex]F.
- For every hour after midnight, the temperature drops by [tex]\( 2^\circ \)[/tex].
### Equation Analysis:
#### Option A: [tex]\( t = 2h + 32 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = 2(0) + 32 \Rightarrow t = 32^\circ \)[/tex]F.
- Temperature Drop: When [tex]\( h = 1 \)[/tex], [tex]\( t = 2(1) + 32 = 34^\circ \)[/tex]F. This is an increase, not a drop.
Since the temperature rises with increasing [tex]\( h \)[/tex], this equation is not correct.
#### Option B: [tex]\( t = -2h + 32 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = -2(0) + 32 \Rightarrow t = 32^\circ \)[/tex]F.
- Temperature Drop: When [tex]\( h = 1 \)[/tex], [tex]\( t = -2(1) + 32 = 30^\circ \)[/tex]F. This is a drop of [tex]\( 2^\circ \)[/tex], which matches the given information.
This equation decreases correctly by [tex]\( 2^\circ \)[/tex] per hour, hence it is a valid model of the temperature change.
#### Option C: [tex]\( t = 32h - 2 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = 32(0) - 2 \Rightarrow t = -2 \)[/tex]F. This does not match the initial temperature of [tex]\( 32^\circ \)[/tex]F at midnight.
Hence, this equation is incorrect.
#### Option D: [tex]\( t = -32h + 2 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = -32(0) + 2 \Rightarrow t = 2 \)[/tex]F. This does not match the initial temperature of [tex]\( 32^\circ \)[/tex]F at midnight.
Therefore, this equation is incorrect.
### Conclusion
Based on the given conditions and evaluating each equation:
The correct equation representing the temperature [tex]\( t \)[/tex] at hour [tex]\( h \)[/tex] is:
[tex]\[ \boxed{t = -2h + 32} \][/tex]
Thus, option (B) is the correct answer.
### Given Information:
- The initial temperature at midnight ([tex]\( h = 0 \)[/tex]) is [tex]\( 32^\circ \)[/tex]F.
- For every hour after midnight, the temperature drops by [tex]\( 2^\circ \)[/tex].
### Equation Analysis:
#### Option A: [tex]\( t = 2h + 32 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = 2(0) + 32 \Rightarrow t = 32^\circ \)[/tex]F.
- Temperature Drop: When [tex]\( h = 1 \)[/tex], [tex]\( t = 2(1) + 32 = 34^\circ \)[/tex]F. This is an increase, not a drop.
Since the temperature rises with increasing [tex]\( h \)[/tex], this equation is not correct.
#### Option B: [tex]\( t = -2h + 32 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = -2(0) + 32 \Rightarrow t = 32^\circ \)[/tex]F.
- Temperature Drop: When [tex]\( h = 1 \)[/tex], [tex]\( t = -2(1) + 32 = 30^\circ \)[/tex]F. This is a drop of [tex]\( 2^\circ \)[/tex], which matches the given information.
This equation decreases correctly by [tex]\( 2^\circ \)[/tex] per hour, hence it is a valid model of the temperature change.
#### Option C: [tex]\( t = 32h - 2 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = 32(0) - 2 \Rightarrow t = -2 \)[/tex]F. This does not match the initial temperature of [tex]\( 32^\circ \)[/tex]F at midnight.
Hence, this equation is incorrect.
#### Option D: [tex]\( t = -32h + 2 \)[/tex]
- Initial Condition (when [tex]\( h = 0 \)[/tex]):
[tex]\( t = -32(0) + 2 \Rightarrow t = 2 \)[/tex]F. This does not match the initial temperature of [tex]\( 32^\circ \)[/tex]F at midnight.
Therefore, this equation is incorrect.
### Conclusion
Based on the given conditions and evaluating each equation:
The correct equation representing the temperature [tex]\( t \)[/tex] at hour [tex]\( h \)[/tex] is:
[tex]\[ \boxed{t = -2h + 32} \][/tex]
Thus, option (B) is the correct answer.
Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. Thank you for visiting IDNLearn.com. For reliable answers to all your questions, please visit us again soon.