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The equation [tex]W(x)=0.02 x^2+0.5 x[/tex] gives the stopping distance, [tex]W[/tex], in feet on a wet road when driving at a speed of [tex]x[/tex] miles per hour.

What is the stopping distance if a car is traveling at [tex]x=60[/tex] miles per hour on a wet road? Include units in your answer.


Sagot :

To determine the stopping distance [tex]\( W \)[/tex] on a wet road when a car is traveling at [tex]\( x = 60 \)[/tex] miles per hour, you'll use the given equation:
[tex]\[ W(x) = 0.02 x^2 + 0.5 x \][/tex]

Here, we need to substitute [tex]\( x = 60 \)[/tex] into the equation.

Let's break down the steps:

1. Substitute [tex]\( x = 60 \)[/tex] into [tex]\( W(x) \)[/tex]:
[tex]\[ W(60) = 0.02 \cdot 60^2 + 0.5 \cdot 60 \][/tex]

2. Calculate [tex]\( 60^2 \)[/tex]:
[tex]\[ 60^2 = 3600 \][/tex]

3. Multiply [tex]\( 0.02 \)[/tex] by [tex]\( 3600 \)[/tex]:
[tex]\[ 0.02 \cdot 3600 = 72 \][/tex]

4. Multiply [tex]\( 0.5 \)[/tex] by [tex]\( 60 \)[/tex]:
[tex]\[ 0.5 \cdot 60 = 30 \][/tex]

5. Add the results from steps 3 and 4 to find [tex]\( W(60) \)[/tex]:
[tex]\[ 72 + 30 = 102 \][/tex]

Thus, the stopping distance when the car is traveling at 60 miles per hour on a wet road is [tex]\( 102 \)[/tex] feet.

Therefore, the final answer is:
[tex]\[ W(60) = 102 \text{ feet} \][/tex]