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The table shows the number of people who rode two different carnival rides during the first hour of the fair on opening day.

\begin{tabular}{|c|c|c|c|}
\cline{2-4}
\multicolumn{1}{c|}{} & Ferris Wheel & Swing Ride & Total \\
\hline
Children & 72 & 24 & 96 \\
\hline
Adults & 126 & 42 & 168 \\
\hline
Total & 198 & 66 & 264 \\
\hline
\end{tabular}

Based on the data in the table, what is the approximate value of [tex]$P$[/tex] (adults who rode a Ferris wheel)?

A. 0.477
B. 0.636
C. 0.848
D. 0.750


Sagot :

To solve for the probability that an adult rode the Ferris Wheel, [tex]\( P(\text{adult rode the Ferris Wheel}) \)[/tex], we should use the data presented in the table.

Here's the step-by-step procedure:

1. Identify the total number of adults:
From the table, the total number of adults is 168.

2. Identify the number of adults who rode the Ferris Wheel:
From the table, the number of adults who rode the Ferris Wheel is 126.

3. Calculate the probability [tex]\( P(\text{adult rode the Ferris Wheel}) \)[/tex]:
The probability is computed by dividing the number of adults who rode the Ferris Wheel by the total number of adults.
[tex]\[ P(\text{adult rode the Ferris Wheel}) = \frac{\text{Number of adults who rode the Ferris Wheel}}{\text{Total number of adults}} = \frac{126}{168} \][/tex]

4. Simplify the fraction:
Divide both the numerator and the denominator by their greatest common divisor (simplifies to [tex]\(\frac{3}{4}\)[/tex]):
[tex]\[ P(\text{adult rode the Ferris Wheel}) = \frac{126}{168} = 0.75 \][/tex]

Therefore, based on the data in the table, the approximate value of [tex]\( P(\text{adult rode the Ferris Wheel}) \)[/tex] is 0.750. The correct answer is:

D. [tex]\( 0.750 \)[/tex]