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What value of [tex]$x$[/tex] is in the solution set of the inequality [tex]$4x - 12 \leq 16 + 8x$[/tex]?

A. [tex]-10[/tex]
B. [tex]-9[/tex]
C. [tex]-8[/tex]
D. [tex]-7[/tex]


Sagot :

To solve the inequality [tex]\(4x - 12 \leq 16 + 8x\)[/tex], we need to follow these steps:

1. Start by simplifying the inequality:
[tex]\[ 4x - 12 \leq 16 + 8x \][/tex]

2. Isolate the variable term [tex]\(x\)[/tex]. To do this, subtract [tex]\(4x\)[/tex] from both sides of the inequality:
[tex]\[ 4x - 12 - 4x \leq 16 + 8x - 4x \][/tex]
Simplifying this gives:
[tex]\[ -12 \leq 16 + 4x \][/tex]

3. Isolate the [tex]\(x\)[/tex]-term further by subtracting 16 from both sides:
[tex]\[ -12 - 16 \leq 4x \][/tex]
Simplifying this gives:
[tex]\[ -28 \leq 4x \][/tex]

4. Solve for [tex]\(x\)[/tex] by dividing both sides by 4:
[tex]\[ \frac{-28}{4} \leq x \][/tex]
Simplifying this gives:
[tex]\[ -7 \leq x \][/tex]

This inequality tells us that [tex]\(x\)[/tex] must be greater than or equal to [tex]\(-7\)[/tex].

Next, we need to check which of the given values [tex]\(-10\)[/tex], [tex]\(-9\)[/tex], [tex]\(-8\)[/tex], or [tex]\(-7\)[/tex] satisfies this inequality.

The values [tex]\(-10\)[/tex], [tex]\(-9\)[/tex], and [tex]\(-8\)[/tex] are all less than [tex]\(-7\)[/tex], so they do not satisfy the inequality. The value [tex]\(-7\)[/tex] is equal to [tex]\(-7\)[/tex] and thus is within the solution set of the inequality.

So, the value of [tex]\(x\)[/tex] that is in the solution set of the inequality [tex]\(4x - 12 \leq 16 + 8x\)[/tex] is:

[tex]\[ \boxed{-7} \][/tex]