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Here is the reformatted and corrected version of the given task:

Solve for [tex] P [/tex]:

[tex]\[
\begin{array}{ll}
\text{For } -1 \ \textless \ x \leq 0, & P = 2x + 12
\end{array}
\][/tex]

(Note: The original question contains inconsistent and unclear information, so the task has been clarified to solve for [tex] P [/tex] in the specified range of [tex] x [/tex].)

Sagot :

GinnyAnsweridn
Certainly! Let's carefully analyze and solve the problem step by step.

Given the equation for [tex]\( P \)[/tex]:
[tex]\[ P = 2x + 12 \][/tex]

We need to evaluate [tex]\( P \)[/tex] for certain values of [tex]\( x \)[/tex].

### Step 1: Identify the specific values for [tex]\( x \)[/tex]

Let's consider the following values of [tex]\( x \)[/tex]:

1. [tex]\( x = -1 \)[/tex]
2. [tex]\( x = 0.5 \)[/tex]

These values are selected to represent different cases within the interval constraints provided.

### Step 2: Calculate [tex]\( P \)[/tex] for [tex]\( x = -1 \)[/tex]

Substitute [tex]\( x = -1 \)[/tex] into the equation [tex]\( P = 2x + 12 \)[/tex]:

[tex]\[ P = 2(-1) + 12 \][/tex]

[tex]\[ P = -2 + 12 \][/tex]

[tex]\[ P = 10 \][/tex]

Hence, for [tex]\( x = -1 \)[/tex], the value of [tex]\( P \)[/tex] is [tex]\( 10 \)[/tex].

### Step 3: Calculate [tex]\( P \)[/tex] for [tex]\( x = 0.5 \)[/tex]

Substitute [tex]\( x = 0.5 \)[/tex] into the equation [tex]\( P = 2x + 12 \)[/tex]:

[tex]\[ P = 2(0.5) + 12 \][/tex]

[tex]\[ P = 1 + 12 \][/tex]

[tex]\[ P = 13 \][/tex]

Hence, for [tex]\( x = 0.5 \)[/tex], the value of [tex]\( P \)[/tex] is [tex]\( 13 \)[/tex].

### Summary

After evaluating the expression [tex]\( P = 2x + 12 \)[/tex] for the given values of [tex]\( x \)[/tex], we have:

- For [tex]\( x = -1 \)[/tex], [tex]\( P = 10 \)[/tex].
- For [tex]\( x = 0.5 \)[/tex], [tex]\( P = 13 \)[/tex].

Thus, the values of [tex]\( P \)[/tex] for the given [tex]\( x \)[/tex] are [tex]\( 10 \)[/tex] and [tex]\( 13 \)[/tex].
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