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2. Name the following binary ionic compounds.

a. [tex]SrI_2 \qquad[/tex]

b. [tex]Li_2O \qquad[/tex]

c. AgF

d. [tex]FeCl_3[/tex]

iron (III) chloride

e. CuO [tex]\qquad[/tex]

Sagot :

GinnyAnsweridn
Sure! Let's go through each of the given binary ionic compounds and provide their names.

a. [tex]\( SrI_2 \)[/tex]
- Step 1: Identify the elements present: Strontium (Sr) and Iodine (I).
- Step 2: Strontium is a metal belonging to Group 2 of the periodic table, and Iodine is a non-metal.
- Step 3: The name of the compound is formed by naming the metal first and the non-metal second with its suffix changed to “-ide”.
- Result: Strontium Iodide

b. [tex]\( Li_2O \)[/tex]
- Step 1: Identify the elements present: Lithium (Li) and Oxygen (O).
- Step 2: Lithium is a metal belonging to Group 1 of the periodic table, and Oxygen is a non-metal.
- Step 3: The name of the compound is formed by naming the metal first and the non-metal second with its suffix changed to “-ide”.
- Result: Lithium Oxide

c. [tex]\( AgF \)[/tex]
- Step 1: Identify the elements present: Silver (Ag) and Fluorine (F).
- Step 2: Silver is a metal, and Fluorine is a non-metal.
- Step 3: The name of the compound is formed by naming the metal first and the non-metal second with its suffix changed to “-ide”.
- Result: Silver Fluoride

d. [tex]\( FeCl_3 \)[/tex]
- Step 1: Identify the elements present: Iron (Fe) and Chlorine (Cl).
- Step 2: Iron is a transition metal and can have multiple oxidation states; here, it is in the +3 oxidation state.
- Step 3: Chlorine is a non-metal.
- Step 4: The name of the compound is formed by naming the metal first, followed by the oxidation state in Roman numerals in parentheses, and then the non-metal second with its suffix changed to “-ide”.
- Result: Iron(III) Chloride

e. [tex]\( CuO \)[/tex]
- Step 1: Identify the elements present: Copper (Cu) and Oxygen (O).
- Step 2: Copper is a transition metal and here, it is in the +2 oxidation state.
- Step 3: Oxygen is a non-metal.
- Step 4: The name of the compound is formed by naming the metal first, followed by the oxidation state in Roman numerals in parentheses, and then the non-metal second with its suffix changed to “-ide”.
- Result: Copper(II) Oxide

So, the names of the binary ionic compounds are:

a. Strontium Iodide

b. Lithium Oxide

c. Silver Fluoride

d. Iron(III) Chloride

e. Copper(II) Oxide
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