Sure, let's analyze the chemical equation:
[tex]\[ \text{HCl} + \text{C}_5\text{H}_5\text{N} \rightleftharpoons \text{Cl}^- + \text{HC}_5\text{H}_5\text{N}^+ \][/tex]
1. Identify the reactants and products:
- Reactants: HCl and C₅H₅N
- Products: Cl⁻ and HC₅H₅N⁺
2. Determine the acid and base among the reactants:
- HCl is a well-known acid because it donates a proton (H⁺).
- C₅H₅N (pyridine) is a base because it accepts a proton (H⁺).
Therefore, in the reactants:
- HCl (acid)
- C₅H₅N (base)
3. Determine the conjugate acid and conjugate base among the products:
- When HCl loses a proton (H⁺), it forms Cl⁻. Thus, Cl⁻ is the conjugate base of HCl.
- When C₅H₅N gains a proton (H⁺), it forms HC₅H₅N⁺. Thus, HC₅H₅N⁺ is the conjugate acid of C₅H₅N.
Therefore, in the products:
- Cl⁻ (conjugate base)
- HC₅H₅N⁺ (conjugate acid)
So, if we drag the labels to the correct locations on the equation, we get:
[tex]\[ \underset{\text{acid}}{\text{HCl}} + \underset{\text{base}}{\text{C}_5\text{H}_5\text{N}} \rightleftharpoons \underset{\text{conjugate base}}{\text{Cl}^-} + \underset{\text{conjugate acid}}{\text{HC}_5\text{H}_5\text{N}^+} \][/tex]
Here are the placements:
- HCl: acid
- C₅H₅N: base
- Cl⁻: conjugate base
- HC₅H₅N⁺: conjugate acid
