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The following reaction occurs in a car's catalytic converter.

[tex]\[ 2 \text{NO} (g) + 2 \text{CO} (g) \longrightarrow \text{N}_2 (g) + 2 \text{CO}_2 (g) \][/tex]

Which answer best describes the reducing and oxidizing processes in this reaction?

A. NO and CO are both reducing agents.
B. NO and CO are both oxidizing agents.
C. The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.
D. The oxidation state of nitrogen in NO changes from 0 to +2, and the oxidation state of carbon in CO changes from +4 to +2 as the reaction proceeds.

Sagot :

GinnyAnsweridn
Let’s break down the reaction and analyze the oxidation states of the elements involved.

The balanced reaction given is:
[tex]\[ 2 \text{NO} (g) + 2 \text{CO} (g) \rightarrow \text{N}_2 (g) + 2 \text{CO}_2 (g) \][/tex]

1. Determining the Oxidation States:
- The oxidation state of nitrogen (N) in nitric oxide ([tex]\(\text{NO}\)[/tex]) is +2.
- The oxidation state of carbon (C) in carbon monoxide ([tex]\(\text{CO}\)[/tex]) is +2.
- In the product nitrogen gas ([tex]\(\text{N}_2\)[/tex]), the oxidation state of nitrogen is 0.
- In the product carbon dioxide ([tex]\(\text{CO}_2\)[/tex]), the oxidation state of carbon is +4.

2. Changes in Oxidation States:
- For nitrogen in [tex]\(\text{NO}\)[/tex] to [tex]\(\text{N}_2\)[/tex]:
[tex]\[ \text{NO} \rightarrow \text{N}_2 \][/tex]
The oxidation state of nitrogen changes from +2 (in [tex]\(\text{NO}\)[/tex]) to 0 (in [tex]\(\text{N}_2\)[/tex]). This is a reduction process (gain of electrons).

- For carbon in [tex]\(\text{CO}\)[/tex] to [tex]\(\text{CO}_2\)[/tex]:
[tex]\[ \text{CO} \rightarrow \text{CO}_2 \][/tex]
The oxidation state of carbon changes from +2 (in [tex]\(\text{CO}\)[/tex]) to +4 (in [tex]\(\text{CO}_2\)[/tex]). This is an oxidation process (loss of electrons).

3. Describing Reducing and Oxidizing Processes:
- The compound [tex]\(\text{NO}\)[/tex] is reduced (the oxidation state of nitrogen decreases from +2 to 0), which means it is acting as an oxidizing agent.
- The compound [tex]\(\text{CO}\)[/tex] is oxidized (the oxidation state of carbon increases from +2 to +4), which means it is acting as a reducing agent.

So, the detailed changes in oxidation states during this reaction are:
- The oxidation state of nitrogen in [tex]\(\text{NO}\)[/tex] changes from +2 to 0.
- The oxidation state of carbon in [tex]\(\text{CO}\)[/tex] changes from +2 to +4.

Conclusion:
The correct answer that best describes the reducing and oxidizing processes in this reaction is:
- The oxidation state of nitrogen in NO changes from +2 to 0, and the oxidation state of carbon in CO changes from +2 to +4 as the reaction proceeds.
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