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What is the sum of the measures of the interior angles of a 12-gon?

A. [tex]$1620^{\circ}$[/tex]
B. [tex]$1800^{\circ}$[/tex]
C. [tex]$1980^{\circ}$[/tex]
D. [tex]$2160^{\circ}$[/tex]


Sagot :

Certainly! Let's determine the sum of the interior angles of a 12-sided polygon, also known as a 12-gon.

To find the sum of the interior angles of any [tex]\( n \)[/tex]-gon, you can use the formula:
[tex]\[ \text{Sum of the interior angles} = (n - 2) \times 180^\circ \][/tex]

Here, [tex]\( n \)[/tex] represents the number of sides of the polygon.

For a 12-gon, [tex]\( n = 12 \)[/tex].

Plug [tex]\( n = 12 \)[/tex] into the formula:
[tex]\[ \text{Sum of the interior angles} = (12 - 2) \times 180^\circ \][/tex]

First, simplify inside the parentheses:
[tex]\[ 12 - 2 = 10 \][/tex]

Next, multiply by [tex]\( 180^\circ \)[/tex]:
[tex]\[ 10 \times 180^\circ = 1800^\circ \][/tex]

So, the sum of the measures of the interior angles of a 12-gon is:
[tex]\[ \boxed{1800^\circ} \][/tex]

Therefore, the answer is [tex]\( 1800^\circ \)[/tex].