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Which would be the next step in solving for matrix [tex]\( A \)[/tex]?

[tex]\[ A + \left[\begin{array}{llll} 3 & -4 & -11 & 24 \end{array}\right] = \left[\begin{array}{llll} 18 & -5 & 0 & -9 \end{array}\right] \][/tex]

A. [tex]\( A = \left[\begin{array}{llll} 16 & -5 & 0 & -9 \end{array}\right] + \left[\begin{array}{llll} 3 & -4 & -11 & 24 \end{array}\right] \)[/tex]

B. [tex]\( A = \left[\begin{array}{llll} 18 & -5 & 0 & -9 \end{array}\right] - \left[\begin{array}{llll} 3 & -4 & -11 & 24 \end{array}\right] \)[/tex]

C. [tex]\( A = \left[\begin{array}{llll} 18 & -5 & 0 & -9 \end{array}\right] - \left[\begin{array}{llll} 3 & -4 & -11 & 24 \end{array}\right] \)[/tex]

D. [tex]\( A = \left[\begin{array}{llll} 16 & -5 & 0 & -9 \end{array}\right] \times \left[\begin{array}{llll} 3 & -4 & -11 & 24 \end{array}\right] \)[/tex]


Sagot :

Sure, let's find the next step in solving for matrix [tex]\( A \)[/tex] based on the given matrices.

We start with the equation:
[tex]\[ A + \left[\begin{array}{llll}3 & -4 & -11 & 24\end{array}\right] = \left[\begin{array}{llll}18 & -5 & 0 & -9\end{array}\right] \][/tex]

To isolate matrix [tex]\( A \)[/tex], we need to subtract [tex]\(\left[\begin{array}{llll}3 & -4 & -11 & 24\end{array}\right] \)[/tex] from both sides of the equation. Here is the detailed step-by-step solution:

1. Write down the original equation:
[tex]\[ A + \left[\begin{array}{llll}3 & -4 & -11 & 24\end{array}\right] = \left[\begin{array}{llll}18 & -5 & 0 & -9\end{array}\right] \][/tex]

2. Subtract [tex]\(\left[\begin{array}{llll}3 & -4 & -11 & 24\end{array}\right]\)[/tex] from both sides:
[tex]\[ A = \left[\begin{array}{llll}18 & -5 & 0 & -9\end{array}\right] - \left[\begin{array}{llll}3 & -4 & -11 & 24\end{array}\right] \][/tex]

3. Perform the subtraction element-wise:
[tex]\[ A = \left[\begin{array}{llll} 18 - 3 & -5 - (-4) & 0 - (-11) & -9 - 24 \end{array}\right] \][/tex]

4. Calculate each element:
[tex]\[ A = \left[\begin{array}{llll} 15 & -1 & 11 & -33 \end{array}\right] \][/tex]

Thus, the resulting matrix [tex]\( A \)[/tex] is:
[tex]\[ A = \left[\begin{array}{llll} 15 & -1 & 11 & -33 \end{array}\right] \][/tex]

So the next step was performing the element-wise subtraction to find the values of matrix [tex]\( A \)[/tex].
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