IDNLearn.com makes it easy to get reliable answers from knowledgeable individuals. Discover prompt and accurate answers from our experts, ensuring you get the information you need quickly.

The Richter scale measures the magnitude, [tex]M[/tex], of an earthquake as a function of its intensity, [tex]I[/tex], and the intensity of a reference earthquake, [tex]I_0[/tex].

[tex]\[ M = \log \left(\frac{I}{I_0}\right) \][/tex]

What is the approximate intensity of an earthquake with a Richter scale magnitude of 4.8? Use a reference intensity of 1.

A. 0.681

B. [tex]$8,492,500$[/tex]

C. 63,096

D. 660,057


Sagot :

To determine the approximate intensity, [tex]\( I \)[/tex], of an earthquake with a Richter scale magnitude of 4.8, given that the reference intensity, [tex]\( I_0 \)[/tex], is 1, we can use the Richter scale formula.

The formula for the Richter scale magnitude [tex]\( M \)[/tex] is:

[tex]\[ M = \log_{10} \left( \frac{I}{I_0} \right) \][/tex]

We are given:
- [tex]\( M = 4.8 \)[/tex]
- [tex]\( I_0 = 1 \)[/tex]

First, we need to isolate [tex]\( I \)[/tex] in this equation. Starting from the given formula:

[tex]\[ 4.8 = \log_{10} \left( \frac{I}{I_0} \right) \][/tex]

Since [tex]\( I_0 = 1 \)[/tex], this simplifies to:

[tex]\[ 4.8 = \log_{10} (I) \][/tex]

To solve for [tex]\( I \)[/tex], we need to rewrite the logarithmic equation in its exponential form. The equation [tex]\( \log_{10} (I) = 4.8 \)[/tex] can be rewritten as:

[tex]\[ I = 10^{4.8} \][/tex]

Now we calculate [tex]\( 10^{4.8} \)[/tex]:

[tex]\[ I \approx 10^{4.8} \approx 63095.7344480193 \][/tex]

Thus, the intensity [tex]\( I \)[/tex] of the earthquake is approximately 63,095. Therefore, the correct answer is:

C. 63,096