Whether you're a student or a professional, IDNLearn.com has answers for everyone. Join our Q&A platform to access reliable and detailed answers from experts in various fields.
Sagot :
Alright, let's solve the problem step-by-step.
1. Identify the Total Number of Cards:
- A standard deck of playing cards has 52 cards.
2. Identify the Number of Aces:
- There are 4 aces in a deck (Ace of Spades, Ace of Hearts, Ace of Clubs, and Ace of Diamonds).
3. Identify the Number of Red Cards:
- There are 26 red cards in a deck (13 Hearts and 13 Diamonds).
4. Identify the Number of Red Aces:
- Out of the 4 aces, 2 are red (Ace of Hearts and Ace of Diamonds).
5. Use the Formula for the Probability of an Event (P(Ace or Red Card)):
- To calculate the probability of drawing a card that is either an Ace or a Red card, we use the formula for the union of two events:
[tex]\[ P(A \cup R) = P(A) + P(R) - P(A \cap R) \][/tex]
- Where:
- [tex]\( P(A) \)[/tex] = Probability of drawing an Ace.
- [tex]\( P(R) \)[/tex] = Probability of drawing a Red Card.
- [tex]\( P(A \cap R) \)[/tex] = Probability of drawing a card that is both an Ace and a Red Card.
6. Calculate Each Probability:
- [tex]\( P(A) \)[/tex] = Number of Aces / Total number of cards = [tex]\( \frac{4}{52} \)[/tex]
- [tex]\( P(R) \)[/tex] = Number of Red Cards / Total number of cards = [tex]\( \frac{26}{52} \)[/tex]
- [tex]\( P(A \cap R) \)[/tex] = Number of Red Aces / Total number of cards = [tex]\( \frac{2}{52} \)[/tex]
7. Combine the Probabilities:
- Plugging the values into our formula:
[tex]\[ P(A \cup R) = \frac{4}{52} + \frac{26}{52} - \frac{2}{52} \][/tex]
- Simplify the fractions:
[tex]\[ P(A \cup R) = \frac{4 + 26 - 2}{52} = \frac{28}{52} \][/tex]
8. Simplify the Final Answer:
- To reduce the fraction [tex]\( \frac{28}{52} \)[/tex], find the greatest common divisor (GCD) of 28 and 52, which is 4:
[tex]\[ \frac{28}{52} = \frac{28 \div 4}{52 \div 4} = \frac{7}{13} \][/tex]
Therefore, the probability that the card drawn is an Ace or a Red card is [tex]\( \frac{7}{13} \)[/tex].
1. Identify the Total Number of Cards:
- A standard deck of playing cards has 52 cards.
2. Identify the Number of Aces:
- There are 4 aces in a deck (Ace of Spades, Ace of Hearts, Ace of Clubs, and Ace of Diamonds).
3. Identify the Number of Red Cards:
- There are 26 red cards in a deck (13 Hearts and 13 Diamonds).
4. Identify the Number of Red Aces:
- Out of the 4 aces, 2 are red (Ace of Hearts and Ace of Diamonds).
5. Use the Formula for the Probability of an Event (P(Ace or Red Card)):
- To calculate the probability of drawing a card that is either an Ace or a Red card, we use the formula for the union of two events:
[tex]\[ P(A \cup R) = P(A) + P(R) - P(A \cap R) \][/tex]
- Where:
- [tex]\( P(A) \)[/tex] = Probability of drawing an Ace.
- [tex]\( P(R) \)[/tex] = Probability of drawing a Red Card.
- [tex]\( P(A \cap R) \)[/tex] = Probability of drawing a card that is both an Ace and a Red Card.
6. Calculate Each Probability:
- [tex]\( P(A) \)[/tex] = Number of Aces / Total number of cards = [tex]\( \frac{4}{52} \)[/tex]
- [tex]\( P(R) \)[/tex] = Number of Red Cards / Total number of cards = [tex]\( \frac{26}{52} \)[/tex]
- [tex]\( P(A \cap R) \)[/tex] = Number of Red Aces / Total number of cards = [tex]\( \frac{2}{52} \)[/tex]
7. Combine the Probabilities:
- Plugging the values into our formula:
[tex]\[ P(A \cup R) = \frac{4}{52} + \frac{26}{52} - \frac{2}{52} \][/tex]
- Simplify the fractions:
[tex]\[ P(A \cup R) = \frac{4 + 26 - 2}{52} = \frac{28}{52} \][/tex]
8. Simplify the Final Answer:
- To reduce the fraction [tex]\( \frac{28}{52} \)[/tex], find the greatest common divisor (GCD) of 28 and 52, which is 4:
[tex]\[ \frac{28}{52} = \frac{28 \div 4}{52 \div 4} = \frac{7}{13} \][/tex]
Therefore, the probability that the card drawn is an Ace or a Red card is [tex]\( \frac{7}{13} \)[/tex].
Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to helping you again soon.